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charle [14.2K]
2 years ago
10

How many trips can a truck with a 1 by 2 meter cylindrical tank take to fill a 890,000 liters tank?

Mathematics
1 answer:
Reil [10]2 years ago
4 0
Tank diameter = 1m
radius = 0.5m
height = 2m
Volume of tank of truck = πr²h = 3.142 * 0.5² * 2 = 1.571m³ = 1571 litre

Volume of tank to be filled = 890,000 litre

no. of trips = 890000/1571 = 566.52 ≈ 567 trips
 

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What is this simplified? Please help
Naya [18.7K]

Answer:

The end result is -1/(x + 1)

Step-by-step explanation:

In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.

x^2 + 9x + 8 = (x + 1)(x + 8)

Now that we have this factored we can take the original equation and factor a -1 out of the top.

(-1)(x + 8)/(x + 1)(x + 8)

Since there is an (x + 8) on the top and bottom, we can cancel those.

-1/(x + 1)

6 0
3 years ago
A radar gun was used to record the speed of a swimmer (in meters per second) during selected times in the first 2 seconds of a r
Natalka [10]
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]

the area of each trapezoid is (v(t1)+v(t2))/2 times width

for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8

2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24

3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75

4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7

add them all up
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5.49
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6 0
2 years ago
2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16
Masja [62]

Answer: \frac{x-4}{2x-2}

Step-by-step explanation:

\frac{2x^2+5x+3}{x^2-3x-4} divided by \frac{4x^2+2x-6}{x^2-8x+16} is the same thing as multiplying \frac{2x^2+5x+3}{x^2-3x-4} by \frac{x^2-8x+16}{4x^2+2x-6}.

The equation we get is:

\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}

With this equation, we can factor each equation:

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We can cancel out like terms since they would be dividing each other:

\frac{x-4}{2x-2}

8 0
3 years ago
In the given figure, mWY = 76° and mXZ = 112. What is the difference of the measures of angle WPY and angle XPY?
skelet666 [1.2K]

Please consider the attached image for complete question.

We have been given that measure of arc WY is 76° and and measure of arc XZ is 112°. We are asked to find the difference of of the measures of angle WPY and angle XPY.

First of all we will find the measure of angle WPY using intersecting secants theorem. Intersecting secants theorem states that measure of angle formed by two intersecting secants inside a circle is half the sum of intercepting arcs.

m\angle WPY=\frac{1}{2}(\widehat{WY}+\widehat{XZ})

m\angle WPY=\frac{1}{2}(76^{\circ}+112^{\circ})

m\angle WPY=\frac{1}{2}(188^{\circ})

m\angle WPY=94^{\circ}

We can see that angle WPY and angle XPY are linear angles, so they will add up-to 180 degrees.

m\angle WPY+m\angle XPY=180^{\circ}

94^{\circ}+m\angle XPY=180^{\circ}

94^{\circ}-94^{\circ}+m\angle XPY=180^{\circ}-94^{\circ}

m\angle XPY=86^{\circ}

Now we need to find difference of both angles as:

m\angle WPY-m\angle XPY=94^{\circ}-86^{\circ}

m\angle WPY-m\angle XPY=8^{\circ}

Therefore, the difference of the measures of angle WPY and angle XPY is 8 degrees.

6 0
3 years ago
Read 2 more answers
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