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kumpel [21]
2 years ago
7

I need help on this question

Mathematics
2 answers:
lyudmila [28]2 years ago
5 0
Easy, the answer is: B. 11 3/20
Arisa [49]2 years ago
5 0
2.75 + 2.2 + 1.4 + 3.5 + 1.3 = 11.15
3/20 = 0.15 
The correct answer is C!
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Equivalent ratio to 5 over 8
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10 over 16

Step-by-step explanation:

If you multiply 5 by a number then you have to multiply 8 by the number to keep it equivalent

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Please help <br><br>problem 3 and 4<br>show work<br><br>find the value of x, y and z​
ratelena [41]

Answer:

Step-by-step explanation:

The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.

3. Using the above relationship, ...

short-side/hypotenuse = 8/y = y/(8+23)

y^2 = 8·31

y = 2√62

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long-side/hypotenuse = z/(8+23) = 23/z

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short-side/long-side = 8/x = x/23

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4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,

y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)

z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)

x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)

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3 years ago
Brian invests £990 into his bank account. He receives 2% per year simple interest. How much
nata0808 [166]

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \£990\\ r=rate\to 2\%\to \frac{2}{100}\dotfill &0.02\\ t=years\dotfill &4 \end{cases} \\\\\\ A=990[1+(0.02)(4)]\implies A=990(1.02)(4)\implies A=4039.2

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2 years ago
Norma has a credit card that uses the adjusted balance method. For the first
Stella [2.4K]

Answer:

50

Step-by-step explanation:

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3 years ago
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What is the equation of the line that is perpendicular to y= -3x + 1 and passes through (2,3)?
Aleonysh [2.5K]

Answer:

\large\boxed{y=\dfrac{1}{3}x+2\dfrac{1}{3}}

Step-by-step explanation:

\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=-3x+1\to m_1=-3.\\\\\text{Therefore}\ m_2=-\dfrac{1}{-3}=\dfrac{1}{3}.\\\\\text{The equation of the searched line:}\ y=\dfrac{1}{3}x+b.\\\\\text{The line passes through }(2,\ 3).

\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}

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3 years ago
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