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3 years ago

5

ITS AN EXAM PLEASE HELP

1 answer:

AVprozaik [17]3 years ago

6 0

Answer:

528

Step-by-step explanation:

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Solve the equation for the y-value and choose whether it is a direct variation or inverse variation.

Leona [35]

$\\ \sf\longmapsto xy=7$

Take x to right and divide

$\\ \sf\longmapsto y=\dfrac{7}{x}$

Hence

. $\\ \sf\longmapsto y\propto \dfrac{1}{x}$

Inverse variation

7 0

2 years ago

Select the two values of x that are roots of this equation x^2-5x+2=0

Nataly [62]

The roots of the equation is x = 4.56 OR x = 0.44

<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

$x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}$

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

$x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}$

$x =\frac{5 \pm \sqrt{25-8} }{2}$

$x =\frac{5 \pm \sqrt{17} }{2}$

$x =\frac{5 + \sqrt{17} }{2}$ OR $x =\frac{5 - \sqrt{17} }{2}$

$x =\frac{5 + 4.12}{2}$ OR $x =\frac{5 - 4.12}{2}$

$x =\frac{9.12}{2}$ OR $x =\frac{0.88}{2}$

x = 4.56 OR x = 0.44

Hence, the roots of the equation is x = 4.56 OR x = 0.44

Learn more on Quadratic equation here: brainly.com/question/8649555

#SPJ1

3 0

2 years ago

What are the solutions of the quadratic equation below? -7x2 - 23x + 10 = 0 A. B. C. D.

-BARSIC- [3]

Answer:

There are no like terms.

7 0

2 years ago

Read 2 more answers

Tim has to write two papers worth 50 points each. To pass, he has to get at least 45% of the total points. However, scoring less

lions [1.4K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Based on the above situation the graph that <span>represents the region in which Tim fails is the graph A. </span>

4 0

3 years ago

Read 2 more answers

what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))

xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

$FG=9,GH=7,CD=24$

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}DE=FG$

$DE=2(FG)$

$DE=2(9)$

$DE=18$

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

$\dfrac{1}{2}CE=GH$

$CE=2(GH)$

$CE=2(7)$

$CE=14$

Now, the perimeter of the triangle CDE is:

$Perimeter=CD+DE+CE$

$Perimeter=24+18+14$

$Perimeter=56$

Therefore, the perimeter of the triangle CDE is 56 units.

7 0

3 years ago