Question

A shipping container is in the shape of a right rectangular prism with a length of 13.5 feet, a width of 4 feet, and a height of 7.5 feet. The container is completely filled with contents that weigh, on average, 0.56 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?

Answer 1

Answer: 227 pounds.

Step-by-step explanation:

By definition, the volume of a rectangular prism can be calculated with the following formula:

$V=lwh$

Where "w" is the width of the rectangular prism, "l" is the length and "h" is the height of the rectangular prism.

In this case you know that:

$l=13.5\ ft\\\\w=4\ ft\\\\h= 7.5 ft$

Substituting values into the formula, you get that the volume of the shipping container is:

$V=(13.5\ ft)(4\ ft)( 7.5 ft)\\\\V=405\ ft^3$

You know that it was completely filled with  contents that weigh 0.56 pound per cubic foot, approximately. Then, its density is:

$d=0.56\ \frac{lb}{ft^3}$

Since:

$d=\frac{m}{V}$

Where "m" is mass and "V" is volume, you can susbstitute values and solve for "m":

$0.56\ \frac{lb}{ft^3}=\frac{m}{405\ ft^3}\\\\(0.56\ \frac{lb}{ft^3})(405\ ft^3)=m\\\\m\approx227\ lb$