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anygoal [31]
3 years ago
12

Mark is adding X and -4. He finds the LCD to be 3x. What should he do next to find the sum?

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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The sum of two non-zero numbers a and b equals the sum of their reciprocals. If a+b≠0, what is the product of the two numbers?
Vadim26 [7]

Answer:

ab = 1

Step-by-step explanation:

A Reciprocal of a number is a number which when multiplied by the original number yields the multiplicative number, 1.

So the reciprocal of x would be x⁻¹ or ¹⁄ₓ

The information we are given states that the sum of the two non-zero numbers a and b equals the sum of their reciprocals.

So we can write this into an equation and solve,

(See image)

Once we solve, we get the equation (ab-1)(a+b) = 0

We are given info that a+b≠0

So for the above equation to be true, ab-1 has to equal 0

For <em>this</em> to be true, the product ab must equal 1

7 0
3 years ago
On Monday, 351 students went on a trip to the zoo. All 7 buses were filled and 8 students had to travel in cars. How many studen
ira [324]

Answer:

49

Step-by-step explanation:

(351-8)/7 = 49

7 0
3 years ago
Read 2 more answers
2x - 6y = 12<br> 2x – 4y = 8
Alenkasestr [34]

Answer:

true

Step-by-step explanation:

7 0
2 years ago
What is 6 divied 192 please show work
suter [353]
The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.

So we will approach this is in two ways.

If this was meant to be "divided by" then it would look like this:
6 / 192

If this was meant to be "divided to" then it would look like this:
192 / 6

Let us first solve for the first possible problem:
6 / 192 = ?
0.0312

0.0312 would be the answer.

Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?

32 would be the answer.

So 0.0312 and 32 would be two possible answers to this problem.
4 0
3 years ago
Read 2 more answers
Write (1/3i)-(-6+2/3i) as a complex number in standard form
Eddi Din [679]

Answer:

6+\frac{i}{3}

Step-by-step explanation:

\frac{1}{3\imath}-(-6+\frac{2}{3\imath})

\frac{1}{3\imath}+6-\frac{2}{3\imath}

taking like terms together

\frac{1}{3\imath}-\frac{2}{3\imath}+6

taking LCM

\frac{1-2}{3\imath}+6

\frac{-1}{3\imath}+6

taking LCM

\frac{-1+18\imath}{3\imath}

splitting the term

\frac{-1+18\imath}{3\imath}

splitting the term

-\frac{1}{3\imath}+\frac{18\imath}{3\imath}

-\frac{1\times3\imath}{3\imath \times \imath}+6

-\frac{i}{3\imath^2}+6

we know that

\imath^2=-1

putting this value in above equation

\frac{\imath}{3}+6

7 0
3 years ago
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