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lora16 [44]
3 years ago
9

a sample from a mummified bull was taken from a certain place. The sample shows that 71% of the carbon-14 still remains. how old

is the sample
Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Decay of carbon - 14 is exponential in nature . It decays as follows .

N=N_0e^{-\lambda t}  λ is called decay constant .

λ = .693 / T where T is half life .

Half life of carbon-14 is 5700 years

λ = .693 / T

= .693 / 5700

= 12.158 x 10⁻⁵ year⁻¹

N=N_0e^{-\lambda t}

N = .71 N₀

.71 N_0 =N_0e^{-\lambda t}

.71  =e^{-\lambda t}

Taking ln on both sides

ln .71 = - λ t

ln .71 = - 12.158 x 10⁻⁵  t

-0.3425 =  - 12.158 x 10⁻⁵  t

t = .3425 / 12.158 x 10⁻⁵

2817  years .

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