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e-lub [12.9K]
3 years ago
14

Solve the equation ln(1+x)=1+ln(x)

Mathematics
2 answers:
kifflom [539]3 years ago
4 0

Answer:

1/(e - 1)  

Step-by-step explanation:

ln (1 + x) = 1 + ln (x)

ln (1 + x) - ln (x) = 1

ln ((1 + x)/x) = 1

(1 + x)/x = e = 1 + 1/x

x = 1/(e - 1)

Shkiper50 [21]3 years ago
3 0

Step-by-step explanation:

the explanations are in the image

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If the angle of elevation of the sun is 61.7° when a building casts a shadow of 56.5 feet, what is the height of the building ro
maksim [4K]

SOLUTION

Let us use a simple diagram to interprete the question

In the diagram above, the dark stuff below represents the shadow and the rectangular bar represents the building. I have labelled the height of the building as h.

So we will use the right-angled triangle formed to find h

As we can see h represents the opposite side and 56.5 feet represents the adjacent side of the right-angle triangle. So we will use TOA

\text{TOA tan }\theta=\frac{opposite}{\text{adjacent}}

So we have

\begin{gathered} \text{ tan }\theta=\frac{opposite}{\text{adjacent}} \\ \text{ tan }61.7\degree=\frac{h}{56.5} \\ 1.8572015=\frac{h}{56.5} \\ \text{cross multiplying, we have } \\ h=1.8572015\times56.5 \\ h=104.931887 \end{gathered}

Hence the answer is 104.9 feet to the nearest tenth

4 0
1 year ago
The value of y varies directly with x. If x = 6, then y = 27. What is the value of y when x = 10 ?
Alik [6]
B - 45 because 27 divided by 6 is 4.5 and then 10x4.5=44
7 0
3 years ago
Find the coordinates of point A(-3,-4) after a rotation 180° counterclockwise about the origin. Then the point is reflected over
nexus9112 [7]
I believe it's (3,4) 
3 0
3 years ago
URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

\large \boxed{ {tan}^{2}  \theta  =  {sec}^{2}   \theta - 1}

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

Since tan is negative in the second quadrant. Hence,

\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

  • tan = -√5/2
3 0
3 years ago
Hi please help me with this i’ll give brainliest if you give a correct answer​
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

a) PR=SU

b) PQ=TU

c) RQ=TS

5 0
3 years ago
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