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aleksklad [387]
2 years ago
9

HELP PLEASE SOMEONE

Mathematics
1 answer:
Rom4ik [11]2 years ago
8 0
f(x)= \frac{x}{2} -2 and g(x)=2 x^{2} +x-3
(f+g)(x) = \frac{x}{2} -2+2 x^{2} +x-3
combining like terms gives you answer choice B

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Combine like terms to simplify the following expressions <br><br> -5a - 4a + b
Sauron [17]

Answer:

-9a + b

Step-by-step explanation:

For this problem, let us factor out the variable a from the terms containing the variable, and apply addition and the distributive property to simplify the terms.

-5a - 4a + b

= a ( -5 + -4 ) + b

= a ( -9 ) + b

= -9a + b

Hence, the simplified expression for -5a - 4a + b is -9a + b.

Cheers.

7 0
3 years ago
Read 2 more answers
Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi
Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

\dfrac{f(b)-f(a)}{b-a}

compute the quantity

\dfrac{f(3)-f(0)}{3}

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6

And so the average rate of change is

\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4

3 0
3 years ago
Hey who can solve this
Galina-37 [17]

Answer:

I need help on that too help pls

Step-by-step explanation:

7 0
2 years ago
The surf instructor has an initial fee of $12 and charges $8 per hour for lessons, which is represented by the equation y = 8x +
Alex_Xolod [135]

Answer:

Step-by-step explanation:

Y=8(32)+12

Y=256+12

Y=268 (Sandra)

Y=8(24)+12

Y=192+12

Y=204 (Bela)

204+268=472

He earns $472/month

4 0
3 years ago
Read 2 more answers
Robert is a high school basketball player. In a particular game, he made some three point shots and some free throws (worth one
Oksanka [162]

Answer:

let t = number of three-point shots

let f = number of free throw shots

Step-by-step explanation:

t + f = 9      (he made a total of 9 shots altogether)

3t + 1f = 23   (number of shots multiplied by their point value)

substitution method:   t = 9 - f

                                    3(9 - f) + f = 23

                                     27 - 3f + f = 23

                                      -2f = -4

                                         f = 2

find 't':                               t + 2 = 9

                                         t = 7

                                         

8 0
3 years ago
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