All categories

3 years ago

HELP PLEASE SOMEONE

Mathematics

1 answer:

Rom4ik [11]3 years ago

8 0

$f(x)= \frac{x}{2} -2$ and $g(x)=2 x^{2} +x-3$
(f+g)(x) = $\frac{x}{2} -2+2 x^{2} +x-3$
combining like terms gives you answer choice B

You might be interested in

Can someone help me with this question?

Lina20 [59]

Answer:1/3

Step-by-step explanation:

gradient equals

$\frac{Y2-Y1}{X2-X1}$

= $\frac{5-3}{10-4}$

= $\frac{2}{6}$

= $\frac{1}{3}$

6 0

2 years ago

The sum of 2 consecutive whole numbers is 206. What are the 2 numbers

Anni [7]

Answer:

102.5, 103.5

Step-by-step explanation:

a+a+1=206

2a+1=206

2a=205

a=102.5

103.5

I think there is a bug here. They can't be whole numbers.

5 0

2 years ago

Read 2 more answers

Evaluate the expression 8p6

Margaret [11]

Answer:

Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !

Step-by-step explanation:

evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...

8 0

3 years ago

Julia has 4 gallons 2 quarts of water. Ally needs the same amount of water but only has 12 quarts. How much more water does ally

skad [1K]

Answer: Ally would need 6 more quarts of water.
Explanation: Since 4 quarts equal 1 gallon, 4*4 = 16 + 2 = 18, Julia would have 18 quarts. Subtract 12 from 18 to get 6 quarts.

5 0

3 years ago

In 4 minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt

kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 minutes, a conveyor belt moves 800 pounds of recyclable

aluminum from the delivery truck to a storage area. A smaller belt

moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are used, find how long it takes to move the cans

to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = $\frac{1}{4}$ shifting/min

Rate of Smaller Belt = $\frac{1}{6}$ shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = $\frac{1}{x}$ shifting/min

Now,

$\frac{1}{4}$ + $\frac{1}{6}$ = $\frac{1}{x}$

⇒ $\frac{6 + 4}{24} = \frac{1}{x}$

⇒ $\frac{10}{24} = \frac{1}{x}$

⇒10x = 24

⇒x = $\frac{24}{10}$ = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0

3 years ago