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sdas [7]
2 years ago
7

Can someone help me with these Algebra 1 questions, they are pretty tough and i need help since i don't fully understand it yet.

Mathematics
1 answer:
Hatshy [7]2 years ago
4 0
I will answer second attachment and after since I can't see the firs attachment



2nd attachment

if x is negative, then the first number gets infinitely small
look at the second number, the first 2 is -2 which is wrong since it should be +2
3rd option is not because if x=-2, then y=1
answer is D


3rd attachment
2nd: f(x)=60*1.15^x
3rd: no xint
6th: after 7.86 years value tripples
7th maybe: after 8 years value is 183.51, not exatly 184.00


4th attachment
nth score is
f(n)=57+4(n-1)
9th is
f(9)=57+4(9-1)
57+32=89
answer is C 89


5th
f(t)=23000(1.02)^t
t=time in years from 23000
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artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

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(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

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(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

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(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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