Answer:
Factor 3y23y2 out of 3y33y3.
3y2(y)−9y23y2(y)-9y2
Factor 3y23y2 out of −9y2-9y2.
3y2(y)+3y2(−3)3y2(y)+3y2(-3)
Factor 3y23y2 out of 3y2(y)+3y2(−3)3y2(y)+3y2(-3).
3y2(y−3)
Step-by-step explanation:
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Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:
In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that 
Determine the rate of change in surface area when r = 20 cm.
This is 
when 
. So
Applying implicit differentiation.
We have two variables, A and r, so:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Line b is the answer, hope this helped
A vertical stretching is the stretching of the graph away from the x-axis.
A vertical compression is the squeezing of the graph towards the x-axis.
A compression is a stretch by a factor less than 1.
For the parent function y = f(x), the vertical stretching or compression of the function is a f(x).
If | a | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of a units.
If | a | > 1, then the graph is stretched vertically by a factor of a units.
For values of a that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
Thus, the equation with the widest graph is 0.3x^2.
Answer:
steeper
Step-by-step explanation:
y = mx + c where m is the slope and c is the y-intercept.
The slope has been changed from 2 to 4. The higher the slope, the steeper it is. Thus, the slope is steeper now.
