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HACTEHA [7]
3 years ago
5

Determine the value of the variable in the product of powers.

Mathematics
2 answers:
aleksandrvk [35]3 years ago
8 0

Answer:

  • <u><em>1. x = - 3</em></u>
  • <u><em>2. y = -9</em></u>
  • <u><em>3. n = 0</em></u>

<u><em></em></u>

Explanation:

The expressions are garbled. The correct expressions to determine the product of powers are:

1. What is the value of x in the product of powers  5^5\cdot 5^x=5^2 ?

  • x =

2. What is the value of y in the product of p^{-3}\cdot p^{-6}=p^y ?

  • y =

3. What is the value of n in th product of  9^2\cdot 9^{-7}\cdot 9^n=9^{-5} ?

  • n =

<h2>Solutions</h2>

<u />

<u>1. What is the value of x in the product of powers </u>5^5\cdot 5^x=5^2<u> ?</u>

Apply the rule of the <em>product of powers with the same base</em> to the left side of the equality.

The product of two powers with the same base is the base raised to the sum of the exponent:

       5^5\cdot5^x=5^{(5+x)}

Now the power on the left side has the same base as the power on the right side, so the exponents are the same:

  • 5 + x = 2
  • x = 2 - 5
  • x = - 3

<u />

<u>2. What is the value of y in the product of </u>p^{-3}\cdot p^{-6}=p^y<u> ?</u>

Again, the product of the two powers on the left side is equal to the common base raised to the sum of the exponents:

On the left side, you get:

         p^{-3}\cdot p^{-6}=p^{(-3-6)}=p^{-9}

Then,

          p^{-9}=p^y\\\\-9=y\\\\y=-9

3. What is the value of n in th product of  9^2\cdot 9^{-7}\cdot 9^n=9^{-5} ?

Same rule:

Left side:

         

       9^2\cdot 9^{-7}\cdot 9^n=9^{(2-7+n)}=9^{(-5+n)}

Left side equal to right side:

         9^{(-5+n)}=9^{-5}\\\\-5+n=-5\\\\n=-5+5\\\\n=0

Sauron [17]3 years ago
8 0

Answer:

Step-by-step explanation:

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