The 400th term is 425.There are floor(√400) = 20 squares in the range 1..400, so the 400th term will be at least 420. There are floor(∛420) = 7 cubes in the range 1..400, so the 400th term may be as high as 427. However, there are
![\lfloor\sqrt[6]{427}\rfloor=2](https://tex.z-dn.net/?f=%5Clfloor%5Csqrt%5B6%5D%7B427%7D%5Crfloor%3D2)
numbers that are both squares and cubes. Consequently, the 400th term will be 427-2 =
425.
The answer is b
hope this helps :)
It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4
There are 10 options for the first "1" and only 1 option for the other two 1's
There are 9 remaining options for the first "2" and only 1 option for the other 2
There are 8 remaining options for the first "3" and only 1 option for the other 3
There are 7 remaining options for the "4"
10 x 1 x 1 x 9 x 1 x 8 x 1 x 7
10 x 9 x 8 x 7 = 5,040
Answer: 5,040
Answer:
19cm
Step-by-step explanation:
An equilateral triangle is a triangle where the length of the 3 sides are the same.
the perimeter is the sum of the 3 sides
for example, if the length of the side of the an equilateral triangle is 5, the perimeter is 5 x 3 = 15
let x = unknown length of side
length after increase = x + 5
(x + 5) x 3 = 72
divide both sides of the equation by 3
x + 5 = 24
subtract 5 from both sides of the equation
x = 24 - 5 = 19cm
First draw six of anything take out one
