All categories

2 years ago

The line plot shows the pieces of ribbon that Terry can choose for her next craft project.

Mathematics

1 answer:

3241004551 [841]2 years ago

4 0

I THINK B but I’m not as sure

You might be interested in

Given ƒ(x) = x + 10 and g(x) = x2 + 5x - 1, find ƒ(3) + g(5).

SashulF [63]

If I’m not mistaken it should be 8x+25. :)
Hope this helps!

7 0

1 year ago

Solve for x. y=4+bx^2

kicyunya [14]

$y=4+bx^2$

$bx^2 = y - 4$

$x^2 = \dfrac{y-4}{b}$

$x = \pm \sqrt{ \dfrac{y-4}{b} }$

3 0

3 years ago

I give brainliest if the answer is correct

nirvana33 [79]

12000 > 3000+25x Or you can write it out as (12000-3000)/25=x

4 0

2 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

3 years ago

Which values have exactly 2 significant figures? Check all that apply.

JulijaS [17]

ANSWER

Options B, C and D have exactly 2 significant figures.

EXPLANATION

To see whether the numbers have exactly 2 significant figures, round all to 2 significant figures. The ones that remains the same have exactly 2 significant figures.

$302\approx 300$ yards to 2.s.f

$980\approx 980$ gallons to 2.s.f

$1200\approx 1200$ feet to 2.s.f

$84\approx 84$ litters to 2.s.f\

$6,040\approx 6,000$ meters to 2.s.f

8 0

3 years ago

Read 2 more answers