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KiRa [710]
3 years ago
13

A= 2; b= 3; c= 4; d= 12

Mathematics
2 answers:
Allisa [31]3 years ago
7 0
Bc= (3)(4)= 12
 12/12=1
Thepotemich [5.8K]3 years ago
4 0
Bc/12
(3)(4)/12
12/12
1
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When the members of a family discussed where their annual reunion should take​ place, they found that out of all the family​ mem
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-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

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By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following values:

a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The total number of family members is the sum of all these values:

T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

We start finding the values from the intersection of the three sets

5 would not go to a park or a beach or to the family​ cottage.

This means that A \cap B \cap C = 5

1 would go to all three places. This means that d = 1.

8 would go to neither a park nor the family​ cottage

This means that:

A \cap C + (A \cap B \cap C) = 8

A \cap C = 3

8 would go to neither a beach nor the family​ cottage

B \cap C + (A \cap B \cap C) = 8

B \cap C = 3

7 would go to neither a park nor a​ beach

A \cap B + (A \cap B \cap C) = 7

A \cap B = 2

15 would not go to the family​ cottage

C = 15

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

15 = c + 3 + 3 + 5

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12 would not go to a​ beach

B = 12

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

12 = b + 3 + 2 + 5

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11 would not go to a​ park

A = 11

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

11 = a + 2 + 3 + 5

a = 1

Now, we can find the total number of family members.

T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 1 + 2 + 4 + 1 + 2 + 3 + 3 + 5

T = 21

The total number of family members is 21.

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