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neonofarm [45]
2 years ago
10

Evaluate the expression when m= 2. m2 - 8m -3​

Mathematics
2 answers:
Alex Ar [27]2 years ago
4 0

Answer:

-15

Step-by-step explanation:

When

  • m=2

Expression get value of:

  • m² - 8n - 3 =
  • 2² - 8*2 - 3 =
  • 4 - 16 - 3 =
  • -15
kati45 [8]2 years ago
3 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{ - 15 }}}}}

Step-by-step explanation:

Given, m = 2

\sf{ {m}^{2}  - 8m - 3}

plug the value of m

\longrightarrow{ \sf{ {2}^{2}  - 8 \times 2 - 3}}

Evaluate the power : 2²

\longrightarrow{ \sf{4 - 8 \times 2 - 3}}

Multiply the numbers: 8 and 2

\longrightarrow{ \sf{4 - 16 - 3}}

The positive and negative integers are always subtracted but posses the sign of the bigger integer :

\longrightarrow{ \sf{ - 12 - 3}}

The negative integers are always added but posses the negative ( - ) sign

\longrightarrow{ \sf{ - 15}}

Hope I helped!

Best regards! :D

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AleksAgata [21]

Answer:

{x | x < - 35 / 2}

Step-by-step explanation:

-4x / 7 > 10

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-4x /7 * 7 > 10 * 7

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Divide both sides by - 4

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2 years ago
I'm having a little bit of trouble figuring out the formula to solve this problem.
goldfiish [28.3K]

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Step-by-step explanation:

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The cost per gram is 0.41/75 = $0.0055

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The cost per gram is 0.82/93 = $0.0088

3) considering Red Prince, 81 gram apple cost $0.36

The cost per gram is 0.36/81 = $0.0044

Since $0.0044 per gram is the lowest of the three, then the type of apple with the least cost per gram is Red prince.

6 0
3 years ago
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Alexxandr [17]

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3 years ago
In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

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3 0
3 years ago
I need both of these help!
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