Based on the calculations, the slowest rate is equal to 4 gallons per minute.
<u>Given the following data:</u>
- Distance from shore = 12 km.
- In-rate = 3 gallons per minute.
- Rowing rate = 24 km per hour.
<h3>How to calculate the slowest rate.</h3>
Let's assume the boat would sink if it takes in more than 20 gallons of water.
<u>Conversion:</u>
- 24 km/h to km/min =
= 0.4 km/min.
Translating the word problem into an algebraic expression, we have;
Therefore, the slowest rate is equal to 4 gallons per minute.
Read more on distance here: brainly.com/question/10545161
Step-by-step explanation:
f(x) = x³ − 6x² + 9x + 3
Take the derivative and evaluate at x = 2.
f'(x) = 3x² − 12x + 9
f'(2) = -3
Check for local minimums or maximums by setting f'(x) equal to 0.
0 = 3x² − 12x + 9
0 = x² − 4x + 3
0 = (x − 1) (x − 3)
x = 1 or 3
Evaluate f(x) at the critical values, and at the end points.
f(0) = 3
f(1) = 7
f(3) = 3
f(5) = 23
f(x) has a minimum of 3 and a maximum of 23.
Answer:
-13x^2+8x-3
Step-by-step explanation:
6 and 3 because I took the assignment as well
Answer: you will win for any distances greater than 190ft.
To find the rate, you’ll first need to find the slope between two points
Slope formula: m=y^2 - y^1 / x^2 - x^1
Plug the equation in: 76-38/4-2
Substitute. subtract, & divide and you get m=19
Then you have to do slop intercept form:
Formula: y-y1= m(x-x1)
Plug in the equation:
Y-38=19(x-2) substitute
Y-38=19-38 distribute
Y= 19x
Then you graph it (I attached a graph pic)
On the graph there’s two lines that intersect at (10,190). For x less than 10, you will run farther than your friends = you will win.
