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2 years ago

Name the property of the equation illustrates. -2.1 x 1 = -2.1

Mathematics

2 answers:

enyata [817]2 years ago

7 0

I believe that the answer would be multiplication but I may be wrong.
Hope this helps!

harina [27]2 years ago

6 0

Answer:

Identity Property of Multiplication

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Simplify (reduce) 8/30 it is a fraction

defon

4/15 is it's lowest terms. 2 is the lowest number that goes into both 8 and 30. It goes into 8 four times, and 30 15 times.
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2 years ago

What is the measure of x?<br>Angles are not necessarily drawn to scale.

Irina18 [472]

Answer:

139°

Step-by-step explanation:

these angles are supplementary angles, meaning that when added together, they equal 180°

so you just need to subtract 41 from 180 which gets you 139.

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Stephanie walks 2/5 miles in 1/4 our what is Stephanie speed in miles per hour

aivan3 [116]

2÷5=0.4
1÷4=0.25
0.4÷0.25=0.016
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2 years ago

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A fireman's water hose shoots 320 kg of water each second against the door of a building. The velocity of the water is 20 m/s an

NeX [460]

Answer:

$6400\ \text{N}$

Step-by-step explanation:

$\dfrac{m}{t}$ = Mass flow rate of water = 320 kg/s

$m$ = Mass of water on the door

$t$ = Time

$v$ = Velocity of water on the door = 20 m/s

Force is given by

$F=\dfrac{m}{t}v\\\Rightarrow F=320\times 20\\\Rightarrow F=6400\ \text{N}$

The average force is exerted by the stream of water is $6400\ \text{N}$ .

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2 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

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3 years ago