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sveticcg [70]
3 years ago
9

Charla has six segments with which to make two triangles. The segments lengths are 2 in., 3 in., 4 in., 5 in., 6 in., and 7 in.

Which are possible side lengths of her two triangles?
2 in., 4 in., 6 in. and 3 in., 5 in., 7 in.
2 in., 5 in., 6 in. and 3 in., 4 in., 7 in.
2 in., 3 in., 4 in. and 5 in., 6 in., 7 in.
2 in., 3 in., 6 in. and 4 in., 5 in., 7 in.
Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
2, 3, 4, 5, 6, 7. Is the correct answer
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Answer:

x = 9

Step-by-step explanation:

Both the triangles are similar, so the corresponding sides are also similar.

That is,

12 / 8 = x / 6

Cross multiply,

x * 8 = 12 * 6

8x = 72

Divide 8 on both sides,

x = 72 / 8

x = 9

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2 years ago
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Find the area of the triangle 10.4 ft 16.9 ft =
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Step-by-step explanation:

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= 87.88 sq ft

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50%

Step-by-step explanation:

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Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq
Arte-miy333 [17]

Answer:

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Step-by-step explanation:

Let

x------> the length of rectangle

y----> the width of rectangle

we know that

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so

120=xy+2x^{2} +2y^{2} -----> equation A

x=y+5 -----> equation B

substitute equation B in equation A

120=y(y+5)+2(y+5)^{2} +2y^{2}\\120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\5y^{2}+25y+50-120=0\\5y^{2}+25y-70=0

using a graphing calculator to resolve the quadratic equation

the solution is

y=2\ cm

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Find the perimeter of rectangle

The perimeter of rectangle is equal to

P=2(x+y)\\P=2(7+2)=18\ cm

3 0
4 years ago
A​ T-shirt is launched from a height of 66 feet with an initial upward velocity of 6464 feet per second. The​ T-shirt is caught
dusya [7]
<span> s = -16t^2 + 64t + 3
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the maximum height occurs when v = 0:
-32t + 64 = 0 when t = 2 sec

the maximum height is
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the range is [ 3, 67] </span>
4 0
4 years ago
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