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sveticcg [70]
3 years ago
9

Charla has six segments with which to make two triangles. The segments lengths are 2 in., 3 in., 4 in., 5 in., 6 in., and 7 in.

Which are possible side lengths of her two triangles?
2 in., 4 in., 6 in. and 3 in., 5 in., 7 in.
2 in., 5 in., 6 in. and 3 in., 4 in., 7 in.
2 in., 3 in., 4 in. and 5 in., 6 in., 7 in.
2 in., 3 in., 6 in. and 4 in., 5 in., 7 in.
Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0
2, 3, 4, 5, 6, 7. Is the correct answer
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Answer:

Step-by-step explanation:

We first have to write the equation for the sequence, then finding the first five terms will be easy. Follow the formatting:

a_n=a_1+d(n-1) and we are given enough info to fill in:

a_n=-35+4(n-1) and

a_n=-35+4n-4 and

a_n=-39+4n or in linear format:

a_n=4n-39 where n is the position of the number in the sequence. We already know the first term is -35.

The second term:

a_2=4(2)-39 so

a_2=8-39 and

a_2=-31

The third term:

a_3=4(3)-39 and

a_3=12-39 so

a_3=-27 and we could go on like this forever, but the nice thing about this is when we know the difference all we have to do is add it to each number to get to the next number.

That means that the fourth term will be -27 + 4 which is -23.

The fifth term then will be -23 + 4 which is -19. You can check yourself by filling in a 5 for n in the equation and solving:

a_5=4(5)-39 and

a_5=20-39 so

a_5=-19

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