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g100num [7]
3 years ago
10

Are two lines that lie in parallel planes always parallel?

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0
Of course not.

-- Take a washable marker, and give your little sister another washable marker.

-- Stand back-to-back in your bedroom, you facing the front wall, and her facing the back wall.

-- When you say 'GO', both of you draw a straight line on the wall.
   Then look at the lines.

-- The front and back walls are parallel planes, but it would be
amazing if the two lines are parallel.  One could even be a
horizontal line and the other a vertical one . . . definitely not parallel. 
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Help!!!! please!!!!<br> thank you!!!!!!
pentagon [3]

Answer:

18) 6x^2-7x-5

19) 20x^2+17x-63

20) 18x^2-20x+2

21) 5x^2+42x+16

Step-by-step explanation:

Perimeter=length×breadth

18) (3x-5)(2x+1)

=6x^2+3x-10x-5

=6x^2-7x-5

19) (4x+9)(5x-7)

=20x^2-28x+45x-63

=20x^2+17x-63

20) (18x-2)(x-1)

=18x^2-18x-2x+2

=18x^2-20x+2

21) (5x+2)(x+8)

=5x^2+40x+2x+16

=5x^2+42x+16

6 0
3 years ago
A batting cage charges a flat fee of $5 to practice and then $1.50 per bucket of balls.
ahrayia [7]

Answer:

im pretty sure its B, i hope it helps

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Enter the correct answer in the box. Write your answer in the form y = mx + b, using the appropriate inequality symbol in place
muminat

Answer:

y > 4x + 1

Step-by-step explanation:

4 0
2 years ago
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Help binomial distributions
Ymorist [56]

We have the formula to compute the probability of having exactly k successed over n trials, given a probability p of success (and implicitly a probability 1-p of failure), which is


P(\text{k successed on n trials}) = \binom{n}{k}p^k(1-p)^{n-k}


Now, the probability of at least 3 successes is the union of the following event: exactly three successes,exactly four successes and exactly five successes.


We can compute their probability and sum them:\binom{5}{3}\left(\frac{3}{7}\right)^3\left(\frac{4}{7}\right)^2 + \binom{5}{4}\left(\frac{3}{7}\right)^4\left(\frac{4}{7}\right)^1 + \binom{5}{5}\left(\frac{3}{7}\right)^5 \approx 0.36788


So, the answer is about 36.79%

3 0
3 years ago
Please help me with the answer!!!
docker41 [41]

5x = 7x - 8

7x - 5x = 8

2x = 8

x = 8 ÷ 2

x = 4

8 0
2 years ago
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