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Stolb23 [73]
3 years ago
10

(4^p∙4^1)^3 simplifies to 4^q

Mathematics
1 answer:
ddd [48]3 years ago
6 0
\bf \left( 4^p\cdot 4^1 \right)^3\impliedby \textit{distributing the exponent}
\\\\
\left(4^{p\cdot 3} \cdot 4^{1\cdot 3} \right)\implies 4^{3p}4^3\impliedby 
\begin{array}{llll}
\textit{same base, different exponent}\\
\textit{add the exponents, keep the base}
\end{array}

what does it give you?
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