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3 years ago

1. 2.5x + 100 = 600 2. 10 = 2x - 4 3. 2x + 5 = 30

Mathematics

1 answer:

Katarina [22]3 years ago

7 0

Answer:

1) 200 2) 7 3) 12.5

Step-by-step explanation:

For god's sake, use a calculator

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Please help me with my maths homework asap. Thank youuu

notka56 [123]

A = 3.141 * (3km^2). Just put that into a calculator and bingo

5 0

3 years ago

Read 2 more answers

A study has shown that the daily amount of milk produced by a dairy cow is normally distributed, with a mean of 6.2 gallons and

V125BC [204]

Answer:

5.5 gallons to 6.9 gallons

Step-by-step explanation:

Daily a cow

produces a mean of 6.2 gallons (average

of 6.2 gallons, meaning they already

found the mean, "averaged" it out for

you) with a deviation of 7 gallons ("give

or take" .7 gallons). On any given day

(throw these words out) 68% of the cows

(don't need this information to answer

the question either, thrown in to confuse

you) will produce an amount of milk

within which of the following ranges?

Just subtract the deviation ("give or

take number").7 gallons from the mean

(average (already determined)) 6.2

gallons which is 5.5 gallons THEN add

the deviation ("give or take number").

7 gallons to the mean (average (already

determined)) 6.2 gallons which is 6.9

gallons. Your answer is A 5.5 gallons to

6.9 gallons. You don't even have to go

crazy on the math on this question you

can rule them all out but A immediately

with subtracting .7 from 6.2.

hope it helps!

4 0

3 years ago

Read 2 more answers

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given $y=\frac{\ln\left(5x)}{x^2}$

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

$y'=\frac{1-2\ln\left(5x)}{x^3}=0$

$x = \sqrt e/5$ is absolute maximum

$y''=\frac{6\ln\left(5x)-5}{x^4}=0$

$x=e^{5/6}/5$ is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

4 0

3 years ago

300 Less Than 3 tenths

Ksju [112]

The answer is -299.7

4 0

3 years ago

I think it’s b but I’m not sure

laila [671]

No, its D

Just look at the rounds mentioned and subtract the scores from higher round with lower round.

Look at A: round 2 score - round 1 score = -2?
-3 -1 = -4 change, not -2 change so it is wrong

Look at B: round 3 score - round 1 score =-1?
-2-1 =-3 change, not -1 change so it is wrong

Look at C: round 3 score - round 2 score =-1?
-2 -(-3) = 1 change, not -1 change so it is wrong

Look at D: round 3 score - round 1 score =-3?
-2-1 = -3 change, matches with -3 so it is correct.

3 0

2 years ago