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STALIN [3.7K]
2 years ago
11

1. 2.5x + 100 = 600 2. 10 = 2x - 4 3. 2x + 5 = 30

Mathematics
1 answer:
Katarina [22]2 years ago
7 0

Answer:

1) 200 2) 7 3) 12.5

Step-by-step explanation:

For god's sake, use a calculator

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a total of $21,000 is invested in two bonds that pay 4% and 7.5% simple interest. The bond with 7.5 % interest rate earned 6 tim
hjlf
21000=a+b
ax.075xt=6xbx.04xt
t cancels out
a=3.2b
21000= 3.2b+b
21000=4.2b
b=5000
a=16000

account with 7.5% had 16000 invested in it.
account with 4% had 5000 invested in it
4 0
3 years ago
Heather finally narrowed her clothing choices for the big party down to three skirts, two tops and four pies of shoes. How many
Zigmanuir [339]
<h3>Answer: 24</h3>

To get this answer, we multiply the values given to us

3*2*4 = 6*4 = 24

So that's why there are 24 different outfits possible.

6 0
3 years ago
Which is equivalent to 64 Superscript one-fourth?
Schach [20]

Answer:

2 RootIndex 4 StartRoot 4 EndRoot

Step-by-step explanation:

we have

64^{\frac{1}{4}}

Decompose the number 64 in prime factors

64=2^{6}=2^{4}2^{2}

substitute

64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}

7 0
2 years ago
Read 2 more answers
Solve the equation 4 sin (x +30°) = 2<br>for 0 &lt; x &lt; 365​
tatuchka [14]

>

4 \sin(x + 30)  = 2 \\  \sin(x + 30 ) =  \frac{2}{4}   \\  \sin(x + 30)  =  \frac{1}{2}  \\  \sin(x + 30)  =  \sin(30)  \\ x + 30 = 30 \\ x = 30 - 30 \\ x = 0

Hence, x = 0°, 180° and 360° <em><u>Ans</u></em>

3 0
2 years ago
Suppose that the functions r and a are defined for all real numbers x as follows. r(x)=2x-1 S(x)=5x write the expressions for (r
NeTakaya

\boxed{(r-s)(x)=-3x-1} \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x} \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Explanation:</h2>

In this exercise, we have the following functions:

r(x)=2x-1 \\ \\ s(x)=5x

And they are defined for all real numbers x. So we have to write the following expressions:

First expression:

(r-s)(x)

That is, we subtract s(x) from r(x):

(r-s)(x)=2x-1-5x \\ \\ Combine \ like \ terms: \\ \\ (r-s)(x)=(2x-5x)-1 \\ \\ \boxed{(r-s)(x)=-3x-1}

Second expression:

(r\cdot s)(x)

That is, we get the product of s(x) and r(x):

(r\cdot s)(x)=(2x-1)(5x) \\ \\ By \ distributive \ property: \\ \\ (r\cdot s)(x)=(2x)(5x)-(1)(5x) \\ \\ \boxed{(r\cdot s)(x)=10x^2-5x}

Third expression:

Here we need to evaluate:

(r+s)(-2)

First of all, we find the sum of functions r(x) and s(x):

(r+s)(x)=2x-1+5x \\ \\ Combine \ like \ terms: \\ \\ (r+s)(x)=(2x+5x)-1 \\ \\ (r+s)(x)=7x-1

Finally, substituting x = -2:

(r+s)(-2)=7(-2)-1 \\ \\ (r+s)(-2)=-14-1 \\ \\ \boxed{(r+s)(-2)=-15}

<h2>Learn more: </h2>

Parabola: brainly.com/question/12178203

#LearnWithBrainly

5 0
3 years ago
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