Answer:
6,690 boxes per hour
Step-by-step explanation:
Given:
Number of boxes fill = 6,021
Time is taken = 0.9 hour
Find:
Number of boxes fill per hour
Computation:
Number of boxes fill per hour = Number of boxes fill (1 hour / Time taken)
Number of boxes fill per hour = 6,021 (1 hour / 0.9 hour)
Number of boxes fill per hour = 6,690
Answer would be 81.
you multiply 3 x 10 x 3, which is 90. then subtract 9 from that and you end up with 81
Answer:
25000%
Step-by-step explanation:
Answer and Step-by-step explanation: <u>Law</u> <u>of</u> <u>deduction</u> is a mathematical logic that states the following:
1) If p happens, then q happens;
2) p is true;
Then, a there is a third statement that is
3) q is also true.
In this question,
If a polynomial is prime, then it cannot be factored.
Statement p is that 5x + 13y is a polynomial and is prime, i.e., p is true.
Statement q is that "it cannot be factored"
Therefore, 5x + 13y cannot be factored.
Answer:
the probability is P=0.012 (1.2%)
Step-by-step explanation:
for the random variable X= weight of checked-in luggage, then if X is approximately normal . then the random variable X₂ = weight of N checked-in luggage = ∑ Xi , distributes normally according to the central limit theorem.
Its expected value will be:
μ₂ = ∑ E(Xi) = N*E(Xi) = 121 seats * 68 lbs/seat = 8228 lbs
for N= 121 seats and E(Xi) = 68 lbs/person* 1 person/seat = 68 lbs/seat
the variance will be
σ₂² = ∑ σ² (Xi)= N*σ²(Xi) → σ₂ = σ *√N = 11 lbs/seat *√121 seats = 121 Lbs
then the standard random variable Z
Z= (X₂- μ₂)/σ₂ =
Zlimit= (8500 Lbs - 8228 lbs)/121 Lbs = 2.248
P(Z > 2.248) = 1- P(Z ≤ 2.248) = 1 - 0.988 = 0.012
P(Z > 2.248)= 0.012
then the probability that on a randomly selected full flight, the checked-in luggage capacity will be exceeded is P(Z > 2.248)= 0.012 (1.2%)
