Question

A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool, find the dimensions of the pool.

Answer 1

x = 26 m is the width of the pool, length: 29+4 = 33 m.

Step-by-step explanation:

We have A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool.

Let the width of the pool = x

Then the length will = (x+4) ,over all  dimensions will be (x+6) by (x+6+4) or (x+10)

Total area - pool area = 372

$(x+10)*(x+6) - x(x+4) = 372\\x^{2}+16x+60-x^{2}-4x = 372\\12x+60 = 372\\12x = 372-60\\12x = 312\\x = 26$

∴ x = 26 ft is the width of the pool, length: 29+4 = 33 ft