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Natali5045456 [20]
3 years ago
10

A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the p

ool walk is 372 square meters more than the area of the pool, find the dimensions of the pool.
Mathematics
1 answer:
motikmotik3 years ago
7 0

x = 26 m is the width of the pool, length: 29+4 = 33 m.

<u>Step-by-step explanation:</u>

We have A rectangular pool is surrounded by a walk 3 meters wide. The pool is 4 meters longer than its width. If the total area of the pool walk is 372 square meters more than the area of the pool.

Let the width of the pool = x

Then the length will = (x+4) ,over all  dimensions will be (x+6) by (x+6+4) or (x+10)

Total area - pool area = 372

(x+10)*(x+6) - x(x+4) = 372\\x^{2}+16x+60-x^{2}-4x = 372\\12x+60 = 372\\12x = 372-60\\12x = 312\\x = 26

∴ x = 26 ft is the width of the pool, length: 29+4 = 33 ft

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saveliy_v [14]

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<h2>Hello!</h2>

The answer is: y=cscx

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I attached a pic of the csc function graphic where you can verify the answer!

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