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katrin2010 [14]
3 years ago
8

PLZ HELP! FACTOR THEN SOLVE x2+17x+16=0

Mathematics
2 answers:
Luda [366]3 years ago
6 0
So most likely what this equation would end up being would be 2x + 17x added together t make 19x + 16 = 0 

Hpe I helped =)

Marina86 [1]3 years ago
3 0
X2+17x+16=0
(x+1)(x+16)=0
x+1=0   x+16=0
x=-1, x=-16
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Can someone help me.
Sauron [17]

Answer:

The answer to your question is: 20°

Step-by-step explanation:

Data

m∠XZY = 40

m∠XZB = 20

Process

1.- Find the measure of ∠ XAB

   ∠XAB = 40°   because AB ║ YZ

2.- Find the measure of ∠ZAB

     ∠ZAB + ∠XAB = 180

    ∠ZAB = 180 - ∠XAB

    ∠ZAB = 180 - 40

    ∠ZAB = 140°

3.- Find the measure of ∠ABZ

    The sum of the internal angles in a triangle equals 180°

     ∠AZB + ∠ZAB + ∠ABZ = 180

     20° + 140° + ∠ABZ = 180

     ∠ABZ = 180 - 20 - 140

    ∠ABZ = 20°

7 0
3 years ago
A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03​% chlorine. Starting at tequals​0, city water conta
Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is  

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.  

Remember, 1 h = 60 minutes. The initial value problem is  

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x =  - 6* 10⁻⁴*(3x - 10⁻¹)               x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us  

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C    or    |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).  

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then  

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If  t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

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Step-by-step explanation:

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Answer:

23

Step-by-step explanation:

-26-(-49)=-26+49=23

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when squeaky stands up to the mean girls

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