Step-by-step explanation:
So in the equation given, y = 2x - 3
you substitute x for whats given in the table in the x column.
Example
In the graph the first number under the x colum is -1.
y = 2x - 3 in the equation you take out x and put -1.
So now the equation becomes y = 2 × -1 - 3.
Using bedmas to solve the question you should get -5
Which now means y = -5
To plot the point now x would be -1 and y would be -5 (-1, -5)
Same thing for the second number in the x Column.
y = 2 × 1 - 3 which equals -1
To plot it
x = 1 y = -1. (1, -1)
And for the last number 3.
Agai. You substitute x for 3 which makes the equation y = 2 × 3 - 3
this gives you 3 and to plot it
x would be 3 and y would be 3
Answer:
The midsegment of a trapezoid is parallel to each base, and its length is one-half the sum of the lengths of the bases.
Step-by-step explanation:
Answer:
its 65. bcuz you add it all together
Step-by-step explanation:
1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
