Answer:
The final temperature of the water is 28.98 degree Celsius.
Explanation:
It is given that,
Mass of sample of water, m = 52 grams
Initial temperature,
Heat absorbed,
The specific heat of water is
We need to find the final temperature of the water. The heat absorbed is given by the formula as follows :
So, the final temperature of the water is 28.98 degree Celsius.
Answer:
The final pressure is approximately 0.78 atm
Explanation:
The original temperature of the gas, T₁ = 263.0 K
The final temperature of the gas, T₂ = 298.0 K
The original volume of the gas, V₁ = 24.0 liters
The final volume of the gas, V₂ = 35.0 liters
The original pressure of the gas, P₁ = 1.00 atm
Let P₂ represent the final pressure, we get;
∴ The final pressure P₂ ≈ 0.78 atm.
Answer:
Protons, electrons, same in that order is the answer.
Explanation:
this has to do with the periodic table information.
Answer:
52.5
Explanation:
how you get that is you divide be 3 to get the answer
Answer: 110.2 lbs
Explanation: First, let's determine how many kg the patient masses. Since the dose is 3.000 mg/kg we can convert that to 0.003000 g/kg. So
0.1500 g / 0.003000 g/kg = 50 kg.
So we know the patient has a weight of 50 kg. Now we simply multiply by 2.20462 to get lbs. So
50 kg * 2.20462 lbs/kg = 110.231 lbs
Rounding to 1 decimal place gives 110.2 lbs