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blondinia [14]
3 years ago
5

HELLPP!!! plz!! im confused.

Chemistry
2 answers:
lara [203]3 years ago
7 0
The reaction reaches equilibrium at 2.75 seconds
pav-90 [236]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Equilibrium is defined as the condition when the concentration of the reactants and products are constant. The ratio of their concentration remains constant, it does not vary.

The forward reaction and backward reaction occur at the same rate.

Rate of forward reaction = Rate of backward reaction

From the graph, it is clearly visible that the reaction reached equilibrium a 2.75 seconds, where the concentration of reactants and concentration of products are constant. After this point, the concentration of products starts to increase and the concentration of reactants starts to decrease.

Hence, the correct answer is Option A.

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Large samples... also can be small as well but usually bigger is better
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A sample of an ideal gas has a volume of 0.500 L at 25 degrees celcius and 1.20 atm pressure. What is its volume at 75 degrees c
NemiM [27]
The ideal gas law is PV= nRT.
First you need to manipulate the equation to splice for volume,
Which will be V= nRT/P

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Dmitry_Shevchenko [17]
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7 0
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5. Given 18.5 grams of CHA and 24.0 grams of Oz the following reaction occurs. Calculate the number of grams of
ehidna [41]

Answer:

16.5 g of CO₂ are produced by 18.5 of methane and 24 g of O₂

Explanation:

This is a reaction of combustion:

CH₄ +  2O₂  →  CO₂  + 2H₂O

1 mol of methane react to 2 moles of oxygen in order to produce 1 mol of carbon dioxide and 2 moles of water.

First of all, we determine the moles of each reactant:

18.5 g . 1mol/ 16g = 1.15 moles of methane

24 g . 1mol / 32g = 0.75 moles of oxygen

Now, we determine the limiting reactant:

1 mol of methane reacts to 2 moles of oyxgen

1.15 moles of methane may react to (1.15 . 2) /1 = 2.3 moles.

We only have 0.75 moles of O₂ and we need 2.3, that's why the oxygen is the limiting reagent, because we do not have enough oxygen for the reaction.

2 moles of O₂ produce 1 mol of CO₂

Then 0.75 moles may produce (0.75 . 1) /2 = 0.375 moles of CO₂

We convert the moles to mass → 0.375 mol . 44g /mol = 16.5 g

7 0
3 years ago
When 5.00 g of NH4NO3 is dissolved in 100.0 g of water in a styrofoam cup, the T = - 3.82 ^°C. Is the process of dissolving ammo
miv72 [106K]

Answer:

The process is endothermic.

Heat is 26,9 kJ/mol

Explanation:

The dissolution of NH₄NO₃ in water is:

NH₄NO₃ → NH₄⁺ + NO₃⁻

As the change of temperature in the cup is ΔT = -3,82°C

<em>The process is endothermic</em>. Because the temperature is decreasing in the process. That means the process needs heat.

Assuming the  heat capacity of the solution is 4.18 J/Kg :

q = -C×m×ΔT

Where q is heat, C is heat capacity (4,18J/Kg), m is mass (105g) and ΔT is change in temperature (-3,82°C)

q = 1677 J ≈ <em><u>1,68kJ</u></em>

The moles of NH₄NO₃ dissolved are:

5,00g × (1mol / 80,043g) = <em><u>0,0625 moles</u></em>

That means heat of this process in kJ/ mol is:

1,68kJ / 0,0625moles = <em>26,9 kJ/mol</em>

<em />

I hope it helps!

8 0
3 years ago
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