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Svetllana [295]
4 years ago
15

What is the ph of a neutral solution at a temperature where kw=8.0×10−14?

Chemistry
1 answer:
egoroff_w [7]4 years ago
8 0
A neutral solution is when the H⁺ concentration is equal to OH⁻ concentration.
Since there are equal amounts of both H⁺ and OH⁻, solution is neither basic nor acidic, they both react to form water.
kw is the ionic product of water 
kw = [H⁺][OH⁻]
kw = 8.0 x 10⁻¹⁴
since [H⁺]=[OH⁻]
kw =  [H⁺]²
[H⁺]  = √(8x10⁻¹⁴)
[H⁺] = 2.82 x 10⁻⁷ M
pH is calculated using the following equation 
pH = -log [H⁺] 
pH = -log(2.82 x 10⁻⁷ M)
pH = 6.54
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certain gas occupies 6.24L at pressure of 760 mm Hg.If the pressure is reduced to 60.0mm Hg,what would the new volume be?​
vovikov84 [41]

Answer:

79.04 L

Explanation:

We are given;

Initial Volume; V1 = 6.24L

Initial Pressure; P1 = 760 mm Hg

Final pressure; P2 = 60.0mm Hg

To solve for final volume, we will use Boyles law;

P1•V1 = P2•V2

Let's make V2 which is the final volume the subject;

V2 = (P1•V1)/P2

V2 = (760 × 6.24)/60

V2 = 79.04 L

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5 0
3 years ago
How much positive charge is in 0.7 kg of lithium? with each atom having 3 protons and 3 electrons. The elemental charge is 1.602
hichkok12 [17]

Explanation:

As a neutral lithium atom contains 3 protons and its elemental charge is given as 1.602 \times 10^{-19} C. Hence, we will calculate its number of moles as follows.

          Moles = \frac{mass}{\text{molar mass}}

                     = \frac{0.7 \times 1000 g}{7 g/mol}

                     = 100 mol

According to mole concept, there are 6.023 \times 10^{23} atoms present in 1 mole. So, in 100 mol we will calculate the number of atoms as follows.

        No. of atoms = 100 \times 6.023 \times 10^{23}

                               = 6.023 \times 10^{25} atoms

Since, it is given that charge on 1 atom is as follows.

                     3 \times 1.602 \times 10^{-19}C

                    = 4.806 \times 10^{-19}C

Therefore, charge present on 6.023 \times 10^{25} atoms will be calculated as follows.

    6.023 \times 10^{25} atoms \times 4.806 \times 10^{-19} C

            28.95 \times 10^{6}C

Thus, we can conclude that a positive charge of 28.95 \times 10^{6}C is in 0.7 kg of lithium.

3 0
3 years ago
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