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Verdich [7]
3 years ago
11

Solve for P2 when P1 = 2.0 atm V1 = 8.0 L and V2 = 32 L This is a Boyle’s law has problem

Chemistry
1 answer:
Ulleksa [173]3 years ago
3 0
P1/V1=P2/V2
2/8=x/32
X=2 multiplied by 32 divide by 8
P2=8atm
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