Answer:
The percent yield of the reaction is 35 %
Explanation:
In the reaction, 1 mol of hydrazine reacts with 1 mol O₂ to produce 1 mol of nitrogen and 2 moles of water.
Let's verify the moles that were used in the reaction.
2.05 g . 1mol/ 32 g = 0.0640 mol
In the 100% yield, 1 mol of hydrazine produce 1 mol of N₂ so If I used 0.0640 moles of reactant, I made 0.0640 moles of products.
Let's use the Ideal Gases Law equation to find out the real moles of nitrogen, I made (real yield).
1atm . 0.550L = n . 0.082 . 295K
(1atm . 0.550L) / 0.082 . 295K = n → 0.0225 moles
Percent yield of reaction = (Real yield / Theoretical yield) . 100
(0.0225 / 0.0640) . 100 = 35%
the answer is d electronic balance
Answer:
Volume occupied by oxygen gas at 15 degree centigrade is equal to
centimeter cube
Explanation:
Assuming Pressure is constant.

where T1 and T2 are temperature in Kelvin
Substituting the give values we get-


Volume occupied by oxygen gas at 15 degree centigrade is equal to
centimeter cube
Answer:
0.18 mol
Explanation:
Given data
- Mass of carbon tetrachloride (solvent): 750 g
- Molality of the solution: 0.24 m
- Moles of iodine (solute): ?
Step 1: Convert the mass of the solvent to kilograms
We will use the relationship 1 kg = 1,000 g.

Step 2: Calculate the moles of the solute
The molality is equal to the moles of solute divided by the kilograms of solvent. Then,
