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olga nikolaevna [1]
3 years ago
11

PLEASE HELP MEEEEEEE

Chemistry
1 answer:
Sliva [168]3 years ago
3 0
Amount of copper= mass / molar mass = 17/64=0.2656
According to the balance equation, amount of hydrogen gas : amount of copper = 1:1
Therefore amount of hydrogen gas is 1:1
Thus mass of hydrogen gas is molar mass x mol= 1 x 0.2656= 0.266g
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melamori03 [73]
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Answer = BaCrO4+2NaNO3</span>
6 0
4 years ago
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You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10
natta225 [31]

Answer:

18,8kg of wood

Explanation:

The energy you need to to raise the temperature of 1000 kg of water from 25.0 to 100.0 °C is:

q = C×m×ΔT

Where: q is heat, C is specific heat of water (4,184J/g°C), m is mass in grams (1000x10³g), and ΔT is 100,0°C - 25,0°C = 75,0°C

Replacing:

q = 4,184J/g°C×1000x10³g×75,0°C

<u><em>q = 3,14x10⁸ J of heat are required</em></u>

<u><em /></u>

Now, if the heating value of dry wood is 16,72 MJ/kg = 16,72x10⁶ J/kg, mass of wood required is:

3,14x10⁸J × (1kg / 16,72x10⁶ J) = <em>18,8 kg of wood are required</em>

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I hope it helps!

5 0
3 years ago
describe a general rule for predicting the motion of an object that is being pushed or pulled by unbalanced forces?
7nadin3 [17]

<span>7th grade activities</span>

Force and Motion

(with Work)

 

2010-2011

 

 

<span>
</span>

Outline of Topics:

<span>1.     </span><span>Describing Motion: Graphing, Speed and Velocity  </span>

<span>2.   Describing Motion: Changing Velocity </span>

<span>3.   Forces, Their Sizes and Direction </span>

<span>4.   Force and Mass </span>

<span>5.   Its a grave matter: gravity and inertia </span>

<span>6.   Weight and Mass </span>

<span>7.   All work and no play: Work and Energy </span>

 

Appendices

<span>1:  7th Grade Vocabulary Related to Force and Motion</span>

<span>2:  Motion Detector Directions</span>

<span>3:  Day 1 Graphs with Focus Question at the End</span>

<span>4:  Day 1 Data Collection Sheet </span>

<span>5:  Day 2 Student Problem Sheet</span>

<span>6:  Day 2 Second Set of Problems</span>

<span>7:  Day 2 Graphs for is the Velocity Changing</span>

<span>8:  Day 3 Student Tables with Questions</span>

<span>9:  Day 4 Frame for Science Notebook</span>

<span>10:  Day 5 Skateboard Prediction and Actual Sheets</span>

<span>11:  Day 6 Data Table</span>

12: Day 7 Student Handout

13: Day 7 Force Arrows

<span>14:  Day 8 Data Analysis</span>

<span>15:  Uncovering Student Ideas in Physical Science probes</span>

<span>16:  National Enquirer advertisements</span>

<span>17: Excerpt from Joy Hakim’s The Story of Science: Newton at the Center, pages 172-183</span>

<span>18:  Directions for converting You Tube videos to another media file</span>

 

<span>
</span>

<span>First topic:  Describing motion</span>

A three-day exercise

Learning goals

<span>Reviewed from 6th grade (day 1): </span>

I can interpret a position versus time line graph to determine types of one-dimensional motion of an object.

I can draw a position versus time line graph given appropriate data.

I can represent changes in motion in a variety of ways, including words, motion arrows, graphs, and by acting out.

(Day 2) I can use the information in a position vs. time graph to determine the speed of an object.

<span>New for 7th grade: I can define velocity.</span>

(Day 3) I can distinguish between speed and velocity.

 

Topic Word Bank

<span> <span><span> <span> Speed </span> <span> Motion </span> </span> <span> <span> Velocity </span> <span> Direction </span> </span> <span> <span> Position </span> <span> Graph </span> </span> <span> <span> Distance </span> <span> Vertical </span> </span> <span> <span> Time </span> <span> Horizontal </span> </span> <span> <span> Rate of change </span> <span> Representation </span> </span> <span> <span> Slope </span> <span> <span>             Negative</span> </span> </span> <span> <span>   </span> <span> <span>             Positive</span> </span> </span> </span></span>

 

<span> <span><span> <span> Sequence of Experiences </span> </span> <span> <span> Day 1: Interpretation of a Position/Time Graph </span> <span> Pairs and whole group </span> <span> 10 minutes </span> </span> <span> <span> Day 1: Creation of a Position/Time Graph </span> <span> Lab groups and whole group </span> <span> 25 minutes </span> </span> <span> <span> Day 1: Making Sense of Multiple Representations </span> <span> Whole Group </span> <span> 10 minutes </span> </span> <span> <span> Day 2: Calculating Speed </span> <span> Pairs and whole group </span> <span> 23 minutes </span> </span> <span> <span> Day 2: Differentiating Speed and Velocity </span> <span> Pairs and whole group </span> <span> 18 minutes </span> </span> <span> <span> Day 2: Exit Slip </span> <span> Individually </span> <span> 5 minutes </span> </span> <span> <span> Day 3 Intro </span> <span> Whole class </span> <span> 3 minutes </span> </span> <span> <span> Day 3:Collecting Initial Data </span> <span> In pairs </span> <span> 12 minutes </span> </span> <span> <span> Day 3:Interpreting Data Parts 1 and 2 </span> <span> In pairs, then groups of 4 </span> <span> 20 minutes </span> </span> <span> <span> Day 3: Student Challenge </span> <span>   </span> <span>   </span> </span> <span> <span> Day 3: Class Discussion </span> <span> Whole class </span> <span> 7 minutes </span> </span> <span> <span> Day 4: Intro </span> <span>   </span> <span>   </span> </span> <span> <span> Day 4:Interpreting Data Parts 3, 4 and 5 </span> <span> Whole class </span> <span>   </span> </span> <span> <span> Day 4: Processing Information </span> <span> Individual and Paired </span> <span>   </span> </span> <span> <span> Day 4: Class Discussion </span> <span> Whole Class </span> <span>   </span> </span> <span> <span> Day 4: Exit Slip </span> <span> Individually </span> <span> 3 minutes </span> </span> </span></span> <span>
</span>

Day 1  <span>Focus Question:  What can be learned from different representations of motion?</span>

Materials and Preparation:

For the class:

<span><span><span><span /></span></span></span>

<span />





6 0
3 years ago
At 460 K, the rate constant for this reaction is k = 5.8 × 10–6 s–1 and the activation energy is Ea = 265 kJ/mol. What is the fr
Misha Larkins [42]

The frequency factor from the calculation is 7.1 × 10^25.

<h3>What is the Arrhenius Equation?</h3>

The Arrhenius theory holds that the reaction between molecules owes to the collision between the reactant species. The reacting molecules must posses energy in excess of a minimum amount called the activation energy.

From the theory;

k = A e^-Ea/RT

k = rate constant

A = collision factor

Ea = activation energy

R = gas constant

T = Absolute temperature

5.8 × 10–6 = Ae^-(265 × 10^3/8.314 × 460)

A = 5.8 × 10^–6/8.1 × 10^-31

A = 7.1 × 10^25

Learn more about Arrhenius theory: brainly.com/question/3920636

5 0
2 years ago
Coffee is a solution of organic substances in water. is it a mixture or compound
german
Coffee is a mixture because no new products are formed. This process is hence a physical reaction and thus, is a mixture.
3 0
3 years ago
Read 2 more answers
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