Answer:
??
Step-by-step explanation:
pls type the question properly have a good day:-)
Answer:
m=(r/n)+0.114r
Step-by-step explanation:
m=monthly payment
r=remaining amount
n=# of months remaining
Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: number of daily text messages a high school girl sends.
This variable has a population standard deviation of 20 text messages.
A sample of 50 high school girls is taken.
The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:
X[bar]≈N(μ;δ²/n)
This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:
Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)
a.
P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836
b.
P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)
P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328
I hope you have a SUPER day!
Answer:
A right triangle
Step-by-step explanation:
Answer: 2(3x + 2y) and 6x + 4y
Step-by-step explanation:
Hi, to answer this question we have to solve the expression.
2(2x + 4y + x − 2y)
First we have to simplify the expression within the brackets.
2 (2x + x +4y -2y)
We have the first equivalent expression. Now to obtain the second expression we apply distributive property:
2 (3x) + 2 ( 2y)
In conclusion 2(3x + 2y) and 6x + 4y are equivalent expressions to 2(2x + 4y + x − 2y).
Feel free to ask for more if it´s necessary or if you did not understand something.