Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
1 answer:
Answer:
Step-by-step explanation:
There are only 2 solutions for none of the rooks can capture any of the other rooks: only if they are laid out in either of the 2 diagonal of the chess board
The number of possible combination for the rock to laid out in 8x8 (64 slots) chess board
possible combination
So the probability is pretty thin
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Part 1)
We have two lines: y = 2-x and y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.
Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3
see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9
The only point that satisfies both equations is
where
x = -2/9
Find y:
y = 2-x = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4 = 8(-2/9) + 4 = 20/9
Thus the only actual solution, being the point where the lines cross,
is the point (-2/9, 20/9)------> (-0.22,2.22)
Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure
the solution is the point (-0.22,2.22)
We have two lines: y = 2-x and y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.
Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3
see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9
The only point that satisfies both equations is
where
x = -2/9
Find y:
y = 2-x = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4 = 8(-2/9) + 4 = 20/9
Thus the only actual solution, being the point where the lines cross,
is the point (-2/9, 20/9)------> (-0.22,2.22)
Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure
the solution is the point (-0.22,2.22)
Answer:
We conclude that the rule for the table in terms of x and y is:
- y = 3x+2
Step-by-step explanation:
The table indicates that there is constant change in the x and y values, meaning the table represents the linear function the graph of which would be a straight line.
We know the slope-intercept form of the line equation
y = mx+b
where m is the slope and b is the y-intercept.
Taking two points
- (-2, -4)
- (-1, -1)
Finding the slope between (-2, -4) and (-1, -1)
We know that the y-intercept can be determined by setting x = 0 and finding the corresponding y-value.
Taking another point (0, 2) from the table.
It means at x = 0, y = 2.
Thus, the y-intercept b = 2
Using the slope-intercept form of the linear line function
y = mx+b
substituting m = 3 and b = 2
y = 3x+2
Therefore, we conclude that the rule for the table in terms of x and y is:
- y = 3x+2