Given:
Three integers, a, b, and c, where c is a positive integer.
The product of a and b is 6.
The product of a and c is -4.
The product of b and c is -6.
To find:
The values of a,b and c.
Solution:
According to the given information:
...(i)
...(ii)
...(iii)
From (ii), we get
...(iv)
From (iii), we get
...(v)
Putting and in (i), we get
Taking square root on both sides, we get
It is given that c is a positive integer. So, it cannot be negative and the only value of c is .
Putting in (iv), we get
Putting in (v), we get
Therefore, the values of a,b,c are .
Answer:
Factor
5 out of 5
x^
2
+
10x
−
15
.
5
(
x^
2
+
2
x
−
3
)
5
(
x
−
1
)
(
x
+
3
)
answer^
Replace x with 1/2 then solve for y:
5(1/2) - 2y = 4
2 1/2 -2y = 4
Subtract 2 1/2 from each side:
-2y = 1 1/2
Divide both sides by -2:
y = 1 1/2 / -2
y = -3/4
Answer:
Step-by-step explanation:
A quadratic in factored form is usually expressed as: where the sign of a and b depends on the sign of the zero. And I said "usually" since sometimes the x will have a coefficient. Anyways in the quadratic there are two zeroes at x=-1 and x=3. This can be written as: . Notice how the signs are different? This is because when you plug in -1 as x you get a factor of (-1+1) which becomes 0 and it makes the entire thing zero since when you multiply by 0, you get 0. Same thing for the x-3 if you plug in x=3. Now a is in front and it can influence the stretch/compression. To find the value of a, you can take any point (except for the zeroes, because it will make the entire thing zero, and you can technically input anything in as a)
I'll use the point (1, -4) the vertex
-4 = a(1+1)(1-3)
-4 = a(2)(-2)
-4 = -4a
1 = a. So yeah the value of a is 1
So the equation is just: