If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal. So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.
Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
An=a1(r)^(n-1)
a1=first term
r=common rati
common ratio is a term divded by previous term
6/3=2
r=2
first term is 3
an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576
the 14th term is 24576
Answer:
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Answer:
300 is your answer
Step-by-step explanation: