A
a) y+6x=5 if x= -1 then y+6(-1)=5 then y = 11
b) same thing if x = 3 then y+6(3)=5 y+18=5 subtract both sides by -18 and leave y on left then add 5+(-18)= 13 then y=13
B same as above
question (a) asks you to solve for y because x is -2
(b) asks you to solve for x because y is known
3x+2y=-6 if y = 3 you write 3x+2(3)=-6 3x+6=-6 move the +6 over to right side by subtracting 6 from both side 3x=-6 + -6 so 3x=-12 to get rid of the 3 and only leave the x you want to divide both side by 3 then x= -12/3 then the answer would be x=-4
Use this formula...
(-4 + 8) / 2 , (8 + (-4)) / 2
From there you get...
4 / 2 , 4 / 2
Simplify and you get
(2 , 2)
Answer:
Step-by-step explanation:
The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.
If no zero's, -4 also can't be its zero.
X^2 -5x -36 = x*x -9x+4x -9*4 = x(x-9) +4(x-9) = (x+4)(x-9)
so the second other factor is x+4 so hope that choice wan being x+4 than this will be right just you missed the sign pf plus
hope this will help you
