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krek1111 [17]
3 years ago
9

Me ajuda ai por favor tenho que entregar amanhã

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d){( \frac{1}{3} x - y) }^{2}  =  ({ \frac{1}{9}x }^{2}  -  \frac{2}{3} xy +  {y}^{2} )

e)

(0.25 - a) ^{2}  = (0.25^{2}  - (2)(0.25)a +  {a}^{2} ) \\  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \:  = ( \frac{1}{16}  -  \frac{1}{2} a +  {a}^{2} )

f)

{( \frac{2x}{3}  -  \frac{1}{2} )}^{2}  = ( \frac{4 {x}^{2} }{9}  -  \frac{2x}{3}   +  \frac{1}{4} )

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Find the variable. m angle BDJ=7y+2 , m angle JDR=2y+7
Anna35 [415]

The value of the variable y is 9 given that BDJ=7y+2  and angle JDR=2y+7

From the attached diagram, we can see that the<u> sum of m<BDJ and m<JDR is complementary</u> (i.e. sums up to 90degrees)

Given the following

m<BDJ = 7y + 2

m<JDR = 2y + 7

Summing up to 90

m<BDJ + m<JDR = 90

7y + 2 + 2y + 7 = 90

7y+2y+2+7 = 90

9y + 9 = 90

9y = 90-9

9y = 81

y = 81/9

y = 9

Hence the value of the variable y is 9

Learn more here: brainly.com/question/17247176

3 0
3 years ago
What is the format of this proof?
elena55 [62]
Divide b from both sides then it should be a equal C therefore if you add be it be the midpoint of a and C because BNB or equal to a C
4 0
3 years ago
Please help I will mark brainlest
spin [16.1K]

Hope this helps, pls mark me brainliest

4 0
3 years ago
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

6 0
3 years ago
Fill the missing values to make the equations true.
taurus [48]
Logarithm properties:

\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b

According to this, we can get:

\displaystyle a)\log_7 3+\log_7 8=\log_7 (3\cdot 8)=\log_724\\\\b) \log_89-\log_85=\log_8  \frac{9}{5}\\\\c)\log_325=2\log_35
3 0
3 years ago
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