Realy easy question for soo many points
1 answer:
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Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :
and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:
which solving for "t" becomes:
So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Answer:
a.P.I=
b.G.S=
Step-by-step explanation:
We are given that a linear differential equation
We have to find the particular solution
P.I=
P.I=
P.I=
P.I= (higher order terms can be neglected
P.I=
b.Characteristics equation
C.F=
G.S=C.F+P.I
G.S=