0.20(150) = 30 basketballs were in the shipment. Since the shipment presumably comprised only footballs and basketballs, the remainder of the shipment must consist of footballs.
150 - 30 = 120 footballs were in the shipment.
Yes you would do a. y =(5) -4 b. y=50-2(5)^2 and c. y= 2^5
Answer:
6025.532
Step-by-step explanation:
assume the unknown value was Y
11328=188% x Y
multiplying both sides by 100 Divide both sides of the equation by 188 we will arrive at:
Y=3x 100/188
Y=6025.532 %
Answer:
Question 1: photographs
Question 2: I made my own ect
Step-by-step explanation:
101 child tickets were sold that day
