Hello!
First of all, we need to find the mean. To find it, we add up all of the scores and divide by the number of tests.
85+93+78+90+88+97+88=619
619/7≈88.43
Mean≈88.43
Now we need to find the median. First we order the numbers from least to greatest.
78,85,88,88,90,93,97
Now we have to find the middle number. As you can see, the number in the middle is 88.
Median: 88
Finally, we need to find the mode. This is the number that appears the most. As you can see, 88 appears twice, while all of the others appear only once. Therefore, our mode is 88.
Mode:88
I hope this helps!
Okay to solve this problem you would simply do this solution. It took me a minute, haven't had to do integers in a while. :D
From 10,000 to 99,999 the numbers divisible by 5 ends in 0 or 5.
The first (most significant) digit can be any of nine from 1 to 9.
The 2nd digit can be any of 10.
The 3rd digit can be any of 10.
The 4th digit can be any of 10.
The 5th digit can be either of 2.
<span>That's 9(10)(10)(10)2=18,000
</span>
I hope this helps.
The probability of rolling 1 number, a four, on a 6-sided number cube, is 1/6.
On the second roll, the probability of rolling 1 number, a four, is again 1/6 (remember theoretical probability for one event does not consider previous rolls).
But the probability of rolling a four on 2 on consecutive rolls will be the probability of the first event times the probability of the second event. Think of it as rolling a four on the first time <em>and</em> the second time, and whenever there is "and" you need to multiply the probabilities. The probability of rolling a four on two consecutive rolls is
(1/6)*(1/6) = 1/36.
Answer:
V=62.83.
Step-by-step explanation: