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3 years ago

Visual encoding is the encoding of____________

Mathematics

2 answers:

4vir4ik [10]3 years ago

8 0

It would be A - Images

Flura [38]3 years ago

3 0

Answer:

Your answer here is images

Step-by-step explanation:

In computers, encoding is the process of putting a sequence of characters (letters, numbers, punctuation, and certain symbols) into a specialized format for efficient transmission or storage. Decoding is the opposite process -- the conversion of an encoded format back into the original sequence of characters. Encoding and decoding are used in data communications, networking, and storage. The term is especially applicable to radio (wireless) communications systems. Visual encoding uses images and neuronal encoding uses sounds. You do not use meanings or acronyms while coding. So that leaves you with your two answers of images and sounds and based on what I have stated here, we can infer that visual encoding uses images, so that is your answer:)

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Question:

prohojiy [21]

Answer:

x = 3/2 + sqrt(17)/2 or x = 3/2 - sqrt(17)/2

Step-by-step explanation:

Solve for x over the real numbers:

x/x - 1 = x - 3 - 2/x

x/x - 1 = 0:

0 = x - 3 - 2/x

0 = x - 3 - 2/x is equivalent to x - 3 - 2/x = 0:

x - 3 - 2/x = 0

Bring x - 3 - 2/x together using the common denominator x:

(x^2 - 3 x - 2)/x = 0

Multiply both sides by x:

x^2 - 3 x - 2 = 0

Add 2 to both sides:

x^2 - 3 x = 2

Add 9/4 to both sides:

x^2 - 3 x + 9/4 = 17/4

Write the left hand side as a square:

(x - 3/2)^2 = 17/4

Take the square root of both sides:

x - 3/2 = sqrt(17)/2 or x - 3/2 = -sqrt(17)/2

Add 3/2 to both sides:

x = 3/2 + sqrt(17)/2 or x - 3/2 = -sqrt(17)/2

Add 3/2 to both sides:

Answer: x = 3/2 + sqrt(17)/2 or x = 3/2 - sqrt(17)/2

3 0

2 years ago

Solve the differential equation.<br><br> (y^2 + xy^2)y' = 1

stira [4]

$(y^2 + xy^2)y' = 1 \ \Rightarrow\ (y^2 + xy^2)\frac{dy}{dx}= 1 \ \Rightarrow\\ \\
y^2(1 + x) \frac{dy}{dx} = 1 \ \Rightarrow\ y^2 dx = \frac{dx}{1 + x}\ \Rightarrow \\ \\
\int y^2 dx =\int \frac{dx}{1 + x} \ \Rightarrow\ \frac{1}{3}y^3 = \ln|1+x| + C\ \Rightarrow \\ \\
y^3 = 3 \ln|1 + x| + 3C\ \Rightarrow\ y = \sqrt[3]{3\ln|1+x| + K},\ \text{where $K = 3C$}
$

6 0

2 years ago

Someone please help, having trouble with this

Dennis_Churaev [7]

Answer:

Step-by-step explanation:

it describes how much the shown graph extends left and right.

Note that 4 is included, but -2 itself not. that's why it's empty and A isn't correct.

B and D are completely inapplicable

pls brainliest

8 0

2 years ago

The team won 18 of its 30 games. What was the team’s won-lost ratio?

NemiM [27]

Answer:

18:12 (accurate)

3:2 (simplified)

Step-by-step explanation:

The team won 18 games out of 30 total games. Find the amount of games lost by simply subtracting 18 with 30:

30 - 18 = 12

The ratio you are trying to find is won to lost, or won:lost. Plug in the corresponding numbers to the corresponding terms:

won:lost ⇒ 18:12

18:12 is the ratio.

If the teacher asks you to simplify, factor both sides. Divide 6 from both sides:

(18)/6 : (12)/6

3:2

3:2 is your simplified ratio.

6 0

3 years ago

•Please help this is due tomorrow, Will give brainliest•

bonufazy [111]

18- j
19- c
20- h
Hope this is right lol

6 0

2 years ago