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3 years ago

Differentiate the following function. y=x(x^2+5)^2

1 answer:

8 0

First, expand to make it easier
y=x(x^2+5)(x^2+5)
y=x(x^4+10x^2+25)
y=x^5+10x^3+25x
differentiation
y'=5x^4+30x^2+25 is the derivitive

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BRAINLIEST GIVEN TO BEST ANSWER

lbvjy [14]

Answer:

Slope = $\frac{1}{4}$

Step-by-step explanation:

Slope of a straight line passing two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

m = $\frac{y_2-y_1}{x_2-x_1}$

From the graph attached,

Line is passing through two points (20, 5) and (80, 20),

Therefore, slope of the line will be,

m = $\frac{20-5}{80-20}$

m = $\frac{1}{4}$

The slope is $\frac{1}{4}$ .

3 0

3 years ago

The interquartile range of a data set is 10 units. What does this represent?

babunello [35]

The central 50 percent of data around average

4 0

3 years ago

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The area of the square is 100 square centimeters. What is the area of the circle?

Setler79 [48]

$length \: of \: 1 \: side = diameter$

$area \: = {l}^{2} \\ 100 = {l}^{2} \\ \sqrt{100} = l \\ l = 10$

$diameter = 2 \times radius \\ 10 = 2 \times radius \\ radius = 5$

$circle \: area = pi \times {r}^{2} \\ circle \: area = 3.142 \times {5}^{2} \\ circle \: area = 3.142 \times 25 \\ circle \: area = 78.55 {cm}^{2}$

6 0

3 years ago

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Point Z is the incenter of ΔSRT. What is mZTB? 24° 31° 35° 62°

Pavlova-9 [17]

The line from an incenter to a vertex bisects the angle that is produced there. You probably notice this in angle ASB and angle ARC. Therefore, angle ZTB is going to be equal to half of the angle measure of BTC. We can do the following:

24+24+35+35+x+x=180 (x represents the two angles in angle BTC when they are bisected)
simplifies to
2x+118=180
Solving for x, we get that x=31.

So angle ZTB=31.

:)

6 0

3 years ago

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Find the value of x in the triangle shown below

Paul [167]

Pythagorean theorem:
$\sqrt{8 {}^{2} + 6 {}^{2} }$
$\sqrt{64 + 36}$
$\sqrt{100}$
$10$

6 0

3 years ago