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Illusion [34]
3 years ago
15

What kind of interaction is not involved in the binding of a substrate to a normally functioning enzyme?

Chemistry
1 answer:
matrenka [14]3 years ago
7 0
It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. The kind of interaction that is NOT involved in the binding of a substrate to a normally functioning enzyme is a<span> permanent covalent bond. Hope this helps.</span>
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Propose a mechanism for the following reaction.
raketka [301]
First, recognize that this is an elimination reaction in which hydroxide must leave and a double bond must form in its place. It is likely an E2 reaction. Here is an efficient mechanism:
1) Pre-reaction: Protonate the -OH to make it a good leaving group, water. H2SO4 or any strong H+ donor works. The water is positively charged but still connected to the compound.
2) E2: Use a sterically hindered base, such as tert-butoxide (tButO-) to abstract the hydrogen from the secondary carbon. [You want a sterically hindered base because a strong, non-sterically hindered base could also abstract a hydrogen from one of the two methyl groups on the tertiary carbon, and that leads to unwanted products, which is not efficient]. As the proton of hydrogen is abstracted, water leaves at the same time, creating an intermediate tertiary carbocation, and the 2 electrons in the C-H bond immediately are used to make a double bond towards the partial positive charge.
In the products we see the major product and water, as expected. Even though you have an intermediate, remember that an E2 mechanism technically happens in one step after -OH protonation. 
5 0
3 years ago
PLEASE HELP!
MArishka [77]
If P=M*V than P=30kg*5m/s. P=150.
P=momentum
M=mass
V=Velocity

Now the last time i have done physics was last year. but i'm pretty confident in this answer. Hope this helps!
8 0
3 years ago
Read 2 more answers
The pressure of a sample of helium in a 200. ml container is 2.0 atm. If the helium is compressed to a pressure of 40. atm witho
Crank

Answer:

V_2=10mL

Explanation:

Hello there!

In this case, according to the given information, it will be possible for us to solve this problem by using the Boyle's law as an inversely proportional relationship between pressure and volume:

P_2V_2=P_1V_1

In such a way, we solve for the final volume, V2, and plug in the initial volume and pressure and final pressure to obtain:

V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{2.0atm*200.mL}{40.atm}\\\\V_2=10mL

Regards!

5 0
3 years ago
Fatima is designing an advanced graphics card for a next-generation video game system. She needs to be able to
Bad White [126]

Answer:

semiconducting,tellurium

Explanation:

just completed the assignment

4 0
3 years ago
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Identify this reaction.
MakcuM [25]
<h3>Answer:</h3>

Single displacement reaction

<h3>Explanation:</h3>
  • Single replacement reaction is a type of reaction in which a reactive element displaces a less reactive element from its compound.
  • The reaction given above; Al + H₂SO₄ → Al₂(SO₄)₃ + H₂ is a single replacement reaction.
  • This is because Aluminium takes the place of hydrogen atoms in sulfuric acid to form aluminium sulfate and hydrogen gas.
  • Double replacement reaction is where cations or anions are exchanged between two compounds to form new compounds.
  • For example the reaction; NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(aq) is a double displacement reaction.
6 0
3 years ago
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