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mixer [17]
3 years ago
15

How does outlets generate electricity???

Computers and Technology
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

"a hole is connected to the wire that brings the electricity back to the breaker box. when you turn on a lamp, the hot part of the outlet allows electricity to flow" I got this info from Google.com

Explanation:

You might be interested in
While researching ideas for cutting energy costs is his company. Hector watches an online video in which a business expert says,
Nataliya [291]
B. Put it in quotes if it is directly quoted as is and cite the source. You should likely also list the source in the works cited but not the phrase itself.
6 0
3 years ago
Read 2 more answers
Identify the careers that require a college degree
Vikentia [17]
Doctor or teacher or an engineer

8 0
3 years ago
Write a while loop that prints userNum divided by 2 (integer division) until reaching 1. Follow each number by a space.
Ksenya-84 [330]

Answer:

   while(userNum>=1){

       System.out.print(userNum/2+" ");

       userNum--;

        }

Explanation:

This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.

<em>import java.util.Scanner;</em>

<em>public class TestClock {</em>

<em>    public static void main(String[] args) {</em>

<em>    Scanner in = new Scanner (System.in);</em>

<em>        System.out.println("Enter the number");</em>

<em>    int userNum = in.nextInt();</em>

<em>    while(userNum>=1){</em>

<em>        System.out.print(userNum/2+" ");</em>

<em>        userNum--;</em>

<em>         }</em>

<em>    }</em>

<em>}</em>

The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of   userNum until reaching 1 (Hence userNum>=1)

3 0
3 years ago
Find the equation of a line which has 10 points the following two coordinates: (4, 0) and (3, 4)​
alex41 [277]

Answer:

The equation of the line is y = -4·x + 16

10 points on the line include;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

Explanation:

The given points through which the line passes are;

(4, 0) and (3, 4)

The slope, 'm', of the line is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore, the slope of the line is (4 - 0)/(3 - 4) = -4

In point and slope form we can get;

\dfrac{y-0}{x-4} = -4

The equation of the line in point and slope form is therefore;

y = -4·(x - 4) = -4·x + 16

The equation of the line in slope and intercept form is

y = -4·x + 16

10 points on the line are obtained using the equation of the line and the desired x-values input into cells on MS Excel and presented here as follows;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

8 0
3 years ago
Instructions
e-lub [12.9K]

Answer:

See explaination

Explanation:

dateType.h

#ifndef dateType_H

#define dateType_H

class dateType

{

public:

void setDate(int month, int day, int year);

//Function to set the date.

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day;

// dYear = year

int getDay() const;

//Function to return the day.

//Postcondition: The value of dDay is returned.

int getMonth() const;

//Function to return the month.

//Postcondition: The value of dMonth is returned.

int getYear() const;

//Function to return the year.

//Postcondition: The value of dYear is returned.

void printDate() const;

//Function to output the date in the form mm-dd-yyyy.

void isLeapYear() const;

dateType(int month = 1, int day = 1, int year = 1900);

//Constructor to set the date

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day; dYear = year;

// If no values are specified, the default

// values are used to initialize the member

// variables.

private:

int dMonth; //variable to store the month

int dDay; //variable to store the day

int dYear; //variable to store the year

};

#endif

dateType.cpp

#include <iostream>

#include "dateType.h"

using namespace std;

void dateType::setDate(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

int dateType::getDay() const

{

return dDay;

}

int dateType::getMonth() const

{

return dMonth;

}

int dateType::getYear() const

{

return dYear;

}

void dateType::printDate() const

{

cout << dMonth << "-" << dDay << "-" << dYear;

}

void dateType::isLeapYear() const

{

if ( dYear%400 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%100 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%4 == 0 )

cout<<endl<<dYear<< " is leap year.\n";

else

cout<<endl<<dYear<< " is not leap year.\n";

}

//Constructor with parameters

dateType::dateType(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

main.cpp

#include<iostream>

#include "dateType.h"

using namespace std;

int main()

{

dateType *dt1=new dateType();

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

dateType *dt2=new dateType(11,14,2019);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt2->setDate(13,32,2016);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt1->setDate(10,10,198);

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

system("pause");

return 0;

}

6 0
3 years ago
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