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trapecia [35]
1 year ago
13

You need to trace the route that a cat 6 utp cable takes through the ceiling and walls of your building. which tool should you u

se?
Computers and Technology
1 answer:
Veronika [31]1 year ago
4 0

We should use Tone Generator to to trace the route that a cat 6 utp cable takes through the ceiling and walls of your building. The tone generator can be used to test the speakers and their electrical wiring, as well as to find the frequency of hearing loss and tinnitus.

A sinusoidal signal is produced by a tone generator at the selected frequency. Can be used as a learning tool for physics as well as to test audio equipment like speakers or earbuds. You may also test the frequency range of tablet speakers.

Learn more about tone generator brainly.com/question/28017740

#SPJ4

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As Juan sat in his biology lab, his instructor was droning on about the techniques of vivisection. Juan kept thinking about the
MaRussiya [10]

Answer:

attending

Explanation:

7 0
3 years ago
Compare Fibonacci (recursion vs. bottom up)
ipn [44]

Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

int FiboNR(int n)

{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

}

return (F[n]);

}

int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

}

7 0
3 years ago
Extend to also calculate and output the number of 1 gallon cans needed to paint the wal. Hint: Use a math function to round up t
Crank

Answer:

Here is the Python program:

import math #import math to use mathematical functions

height = float(input("Enter wall height (feet): ")) #prompts user to enter wall height and store it in float type variable height

width = float(input("Enter wall width (feet): ")) #prompts user to enter wall width and store it in float type variable width

area = height *width #computes wall area

print('Wall area: {} square feet'.format(round(area))) #displays wall area using round method that returns a floating-point number rounded

sqftPerGallon = 350 #sets sqftPerGallon to 350

paintNeeded = area/ sqftPerGallon #computes needed paint

print("Paint needed: {:.2f} gallons".format(paintNeeded)) #displays computed paint needed up to 2 decimal places

cansNeeded = int(math.ceil(paintNeeded)) #computes needed cans rounding the paintNeeded up to nearest integer using math.ceil

print("Cans needed: {} can(s)".format(cansNeeded)) #displays computed cans needed

colorCostDict = {'red': 35, 'blue': 25, 'green': 23} #creates a dictionary of colors with colors as key and cost as values

color = input("Choose a color to paint the wall: ") #prompts user to enter a color

if color in colorCostDict: #if the chosen color is present in the dictionary

    colorCost = colorCostDict.get(color) #then get the color cost from dictionary and stores it into colorCost using get method that returns the value(cost) of the item with the specified key(color)

    cost = cansNeeded * colorCost #computes the cost of purchasing paint of specified color per cansNeeded

  print("Cost of purchasing {} paint: ${}".format(color,colorCostDict[color])) #displays the real cost of the chosen color paint

print("Cost of purchasing {} paint per {} gallon can(s): ${}".format(color,cansNeeded, cost)) #displays the cost of chosen color paint per cans needed.

Explanation:

The program first prompts the user to enter height and width. Lets say user enter 20 as height and 50 as width so the program becomes:

Wall area computed as:

area = height *width

area = 20 * 50

area = 1000

Hence the output of this part is:

Wall area: 1000 square feet                                                                                                                     Next program computes paint needed as:

paintNeeded = area/ sqftPerGallon

Since sqftPerGallon = 350 and area= 1000

paintNeeded = 1000 / 350

paintNeeded = 2.86

Hence the output of this part is:

Paint needed: 2.86 gallons

Next program computes cans needed as:      

cansNeeded = int(math.ceil(paintNeeded))

This rounds the computed value of paintNeeded i.e. 2.86 up to nearest integer using math.ceil so,

cansNeeded = 3                                                                  

Hence the output of this part is:

Cans needed: 3 can(s)                                                                                                                            Next program prompts user to choose a color to paint the wall

Lets say user chooses 'blue'

So the program get the cost corresponding to blue color and multiplies this cost to cans needed to compute the cost of purchasing blue paint per gallon cans. So

cost = cansNeeded * colorCost

cost = 3 * 25

cost = 75

So the output of this part is:

Cost of purchasing blue paint per 3 gallon can(s): $75                                                                                        The screenshot of the program along with its output is attached.

5 0
3 years ago
Create the following matrix M: 1 7 13 19 25 ?-3 9 15 21 27 5 11 17 2329By writing one command and using the colon to address ran
zimovet [89]

Answer:

Matlab code is:

>> M=reshape(1:2:29, 3,5)

>> \%  (a)

>> Va=M(3,:)

>> \% (b)

>> Vb=M(:,4)

>> \% (c)

>> Vc=[M(2,:) M(:,3)']

Explanation:

>>\% \ Making\ the\ Matrix\ With\ required\ terms\ 1\ to\ 29\ with\ spaces\ of\ 5\ in\ three\ rows

>> M=reshape(1:2:29, 3,5)

M =

              1   7  13  19  25

              3  9  15  21  27

              5  11  17  23  29

>> \%  (a)

>>\%\ Slicing\ M\ \ from\ third\ row\ till\ end

>> Va=M(3,:)

Va =\\\ 5\ 11\ 17\ 23\ 29

>> \% (b)

>>\% \ Slicing\ the\4th\ column\ of\  M\ matrix\

>> Vb=M(:,4)

Vb =\\ 19\\ 21\\ 23\\

>> \% (c)

>>\% \ slicing\ the\ 2nd\ row\ and\ 3rd\ column\ of\ M\ Matrix\ and\ combining\ them\ to\ make\ a\ row\ matrix

>> Vc=[M(2,:) M(:,3)']

Vc =\\ 3\ 9\ 15\ 21\ 27\ 13\ 15\ 17

>>

The code is tested and is correct. If you put a semi colon ' ; ' at the end of every statement then your answer will be calculated but matlab doesn't show it until you ask i.e. typing the variable (Va, Vb, Vc )and press enter.

6 0
3 years ago
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of
Mice21 [21]

Solution:

The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.

Thus the required right answer is B.

8 0
3 years ago
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