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3 years ago

Can someone help it has to be a polynomial

Mathematics

2 answers:

8_murik_8 [283]3 years ago

8 0

Length (L) = width (B) + 6

Area = L x B

432^2 = (B + 6) x B

432^2 = B(B + 6)

Alternatively

432^2 = B^2 + 6B

Damm [24]3 years ago

5 0

Answer: Width = 24 inches

Step-by-step explanation:

Let W represent the width of the rectangular sign.

The length of a rectangular sign is 6 inches more than half its width. It means that the length of the rectangular sign would be

W/2 + 6

The formula for determining the area of a rectangle is expressed as

Area = length × width

The area of the sign is 432 square inches. Therefore, the equation for the area of this sign would be

W(W/2 + 6) = 432

W²/2 + 6W = 432

Multiplying both sides of the equation by 2, it becomes

W² + 12W = 864

W² + 12W - 864 = 0

W² + 36W - 24W - 864 = 0

W(W + 36) - 24(W + 36) = 0

W - 24 = 0 or W + 36 = 0

W = 24 or W = - 36

Since W cannot be negative, then

W = 24

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(1 point) Suppose we want a 95% confidence interval for the average amount spent on books by freshmen in their first year at col

Ne4ueva [31]

Answer:

a) $n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40$

So the answer for this case would be n=40 rounded up to the nearest integer

b) For this case if we see the formula for the margin of error

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=16$ represent the population standard deviation

n represent the sample size

Solution to the problem

Part a

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(16)}{5})^2 =39.33 \approx 40$

So the answer for this case would be n=40 rounded up to the nearest integer

Part b

For this case if we see the formula for the margin of error

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

We can see that the margin of error is inversely proportional to the sample size so if we want a samller margin of error we need a LARGER sample

Answer: LARGER

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3 years ago