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Ira Lisetskai [31]

2 years ago

5

A total of 75 cookies and cakes were donated for a bake sale to raise money for the football team. There were four times as many

cookies donated as cakes. How many cookies and cakes were donated

2 answers:

MArishka [77]2 years ago

6 0

Answer:

60

Step-by-step explanation:

15*4 = 60

15+60= 75

Serggg [28]2 years ago

6 0

Answer:

There were 15 cakes and 60 cookies. Hope I helped.

Step-by-step explanation:

75-15=60

15x4=60

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The curved surface area of a right circular cylinder of height 14 cm is 88 cm².

Slav-nsk [51]

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The diameter of the base of the cylinder is 2 cm.

Step-by-step explanation:

<u>GIVEN</u> :

As per given question we have provided that :

➣ Height of cylinder = 14 cm
➣ Curved surface area = 88 cm²

$\begin{gathered}\end{gathered}$

<u>TO</u><u> </u><u>FIND</u> :

in the provided question we need to find :

➠ Radius of cylinder
➠ Diameter of cylinder

$\begin{gathered}\end{gathered}$

<u>USING</u><u> </u><u>FORMULAS</u> :

$\star{\underline{\boxed{\sf{\purple{Csa = 2 \pi rh}}}}}$

$\star{\underline{\boxed{\sf{\purple{d = 2r}}}}}$

➛ Csa = Curved surface area
➛ π = 22/7
➛ r = radius
➛ h = height
➛ d = diameter

$\begin{gathered}\end{gathered}$

<u>SOLUTION</u> :

Firstly, finding the radius of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{Csa = 2 \pi rh}}} \\ \\ \qquad{\longrightarrow{\sf{88 = 2 \times \dfrac{22}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{7} \times r \times 14}}} \\ \\ \qquad{\longrightarrow{\sf{88 =\dfrac{44}{\cancel{7}}\times r \times \cancel{ 14}}}} \\ \\ \qquad{\longrightarrow{\sf{88 =44 \times r \times 2}}} \\ \\ \qquad{\longrightarrow{\sf{88 =88 \times r}}} \\ \\ \qquad{\longrightarrow{\sf{r = \frac{88}{88}}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\pink{r = 1 \: cm}}}}}} \end{gathered}$

Hence, the radius of cylinder is 1 cm.

———————————————————————

Now, finding the diameter of cylinder by substituting the values in the formula :

$\begin{gathered} \qquad{\longrightarrow{\sf{d = 2r}}} \\ \\ \qquad{\longrightarrow{\sf{d = 2 \times 1}}} \\ \\ \qquad{\longrightarrow{\underline{\underline{\sf{\red{r = 2 \: cm}}}}}}\end{gathered}$

Hence, the diameter of the base of the cylinder is 2 cm.

$\rule{300}{2.5}$

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