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shutvik [7]
3 years ago
7

It is asserted that 80% of the cars approaching an individual toll both in New Jersey are equipped with an E-ZPass transponder.

Find the probability that in a sample of six cars: a. All six will have the transponder. b. At least three will have the transponder. c. None will have a transponder. Lind, Douglas. Basic Statistics for Business and Economics (p. 183). McGraw-Hill Education. Kindle Edition.
Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

Option B, At least three will have the transponder

Step-by-step explanation:

<u>Step 1:  Find the probability in 6 cars</u>

6 * %80 or 6 * 0.8

4.8

Answer:  Option B, At least three will have the transponder

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Joseph drove for hours at the speed of 40 km per hours he changed his speed to 65 km for the next 2 hours how far had Joseph dri
daser333 [38]

Answer:

The answer to your question is 450 km

Step-by-step explanation:

Data

First stage                      Second stage

speed 1 = 40 km/h         speed 2 = 65 km/h                      

time 1 = 8 h                     time 2 = 2 h

Process

1.- Write the formula to calculate the speed

    speed = distance / time

-Solve for distance

    distance = speed x time

2.- Calculate the distance of the first stage

    distance 1 = 40 x 8

    distance 1 = 320 km

3.- Calculate the distance of the second stage

    distance 2 = 65 x 2

    distance 2 = 130 km

4.- Calculate the total distance

    Total distance = 320 + 130

                             = 450 km

6 0
3 years ago
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Pleaseee help
natulia [17]

Answer:

B.

Step-by-step explanation:

All computer simulations are designed to test a large number of different scenarios with various sets of data in order to understand each output that certain data generates and ultimately find the best solution. This is the overall main reason why simulations are created. The same applies in this scenario, this simulation will be used to test hypotheses about patterns in the job placement process that are costly or time-consuming to observe in reality. If such tests had to be conducted by actual people it would take months, years, or even decades to generate and analyze all the data.

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3 years ago
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To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t
nikklg [1K]

Answer:

t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805  

p_v =P(t_{(18)}

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_{1}=19.1 represent the mean for the sample mean for 1

\bar X_{2}=23.3 represent the mean for the sample mean for 2

s_{1}=4.818 represent the sample standard deviation for the sample 1

s_{2}=5.559 represent the sample standard deviation for the sample 2

n_{1}=10 sample size selected 1

n_{2}=10 sample size selected 2

\alpha represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis:\mu_{1} \geq \mu_{2}

Alternative hypothesis:\mu_{1} < \mu_{2}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=10+10-2=18

Since is a one sided test the p value would be:

p_v =P(t_{(18)}

Conclusion

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

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3 years ago
Which amount is larger and by how much?
Solnce55 [7]

Answer:

a*(1 -0.5)*(1 +0.5) = 0.75a . . . . the original number "a" is larger

(a/(0.75a) -1) * 100% = 33 1/3% . . . . the original number is larger by 33 1/3% of the revised number

Step-by-step explanation:

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Answer:

answer is 1 5/12 my sister said she did the quizz and helped me answer this

Step-by-step explanation:

have a good day!!

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