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lord [1]
3 years ago
15

Jeremy claims that if a linear function has a slope of the same steepness and the same y-intercept as the linear function in the

graph, then it must be the same function.
Mathematics
2 answers:
andre [41]3 years ago
7 0

Here, we have to examine the equation of the straight line which is denoted by: y = m x +c where "m" is the slope which represents the steepness and c is the y-intercept

Here, the two linear functions have the same slope "m" and the same y-intercept "c". When both these are the same, the two linear functions are representing the same straight line.

Therefore, Jeremy is correct in his argument.


ch4aika [34]3 years ago
4 0
Jeremy is correct.
If two lines have the same slope and y-intercept, they are the same line.
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Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.
Ann [662]

Given:

Consider the given function is:

f(x)=x^2-8x+13

To find:

The average rate of change of the function over the interval -1\leq x\leq 6.

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

We have,

f(x)=x^2-8x+13

At x=-1,

f(-1)=(-1)^2-8(-1)+13

f(-1)=1+8+13

f(-1)=22

At x=6,

f(6)=(6)^2-8(6)+13

f(6)=36-48+13

f(6)=1

Now, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is:

m=\dfrac{f(6)-f(-1)}{6-(-1)}

m=\dfrac{1-22}{7}

m=\dfrac{-21}{7}

m=-3

Therefore, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is -3.

6 0
3 years ago
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Answer:

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