Answer: The answer is two football players pushing a tackling sled because obviously they are going in the same direction. So yeah your answer is B 100% sure!
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Answer:
<em>
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Step-by-step explanation:
The TSA of the cylinder

In Mathematics, 'is' is =
Twice means 2( )
Product means ×
So we have

as the answer.
<u>Answer:</u>
3%
<u>Step-by-step explanation:</u>
We are given the data of number of cars observed waiting in line at the beginning of 2 minute intervals between 3 and 5 p.m. on Friday.
We are to find the probability (in percent) that there is no one in line.
Sum of frequencies = 2 + 9 + 16 + 12 + 8 + 6 + 4 + 2 + 1 = 60
Frequency of no car in line = 2
P (no car in line) = 2 / 60 × 100 = 3.3% ≈ 3%