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Lady_Fox [76]
2 years ago
6

One number is 4 less than a second number. Twice the second number is 16 less than 5 times the first.

Mathematics
1 answer:
andrew-mc [135]2 years ago
7 0

Answer:

1st num=x

sec num=y

4-x<y

2y<16-5x

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Which is the best description of an extraneous solution?
Degger [83]

Answer:

A solution that results in a false statement when substituted back into the original  equation.

Step-by-step explanation:

An extraneous solution is one that arises in a solution of equations, but which on closer inspection is not a solution to the original equation. Therefore, they imply an error in the development of the solution of the equation, so they cannot be taken as a valid solution since, when replacing the result with the missing variable, the equation does not obtain the desired result.

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If a soccer team won 7 of its 13 games, what was their ratio of wins to losses? Assume that there were no tie games.
Yuri [45]

Answer:

Answer : A. 7 to 6

A soccer team won 7 of its 13 game

Total games played by soccer team = 13

Games won by the team = 7

Games lost = total games played - games won

So games lost = 13 - 7 = 6

Now we find the ratio of win to losses

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games lost = 6

So the ratio of won to losses is 7 to 6

Step-by-step explanation:

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12.25m^2 because you’re finding area
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What is an equation of the line that passes through the points (−7,−7) and (−5,−3)?
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Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute
Soloha48 [4]

95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

  • The mean M is 3 and
  • The standard deviation SD is given as 0.25

Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

⇒ 3+0.25 = 3.25 minutes.

Again we move one more space to the right of mean ⇒ M + 2SD

⇒ 3 + (0.25×2) = 3.5 minutes.

Similarly,

Move one space to the left side of mean ⇒ M - SD

⇒ 3-0.25 = 2.75 minutes.

Again we move one more space to the left of mean ⇒ M - 2SD

⇒ 3 - (0.25×2) =2.5 minutes.

The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.

Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)

Therefore, the percent of  red lights that last between 2.5 and 3.5 minutes is 95%

8 0
3 years ago
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