A jar contains 18 apple lollipops, 7 strawberry lollipops, and 10 grape lollipops. Irvin randomly selects a lollipop, gives it t
o his brother, and then randomly selects another lollipop for himself. What is the probability that Irvin selected a grape lollipop for his brother and an apple lollipop for himself?
Write your answer as a percent. Round to the nearest tenth of a percent.
So we need to find the probabilities and multiple them to get our answer. Our first probability is out of 35 lollipops total how likely is it that Irvin picks a grape.
10/35
But then Irvin gets another lollipop for himself. What is the likelihood he will get a apple lollipop out of the 34 (we removed one to give to his brother).
First choice is "1 of 10 grape lollipops from 35 lollipops" The probablity is 10/35 = 2/7 Second choice is "1 of 18 apple lollipops from 34 lollipops" So probablity is 18/34 = 9/17 Between this is AND so you have to these probablities multiply: P(A) = 2/7 * 9/17 = 18/119 P(A) = 18/119 * 100% = 1800/119 % It is approximaly 15,1 %.
